Answer:
23) 36·(3·1/4) = 36·(3/4) = 108/4 = 27
24) (4·2/7)·21 = (8/7)·21 = 168/7 = 24
25) 2(x+4) = 2x+8
26) (5+n)3 = 15+3n
27) (4-3m)8 = 32-24m
28) -3(2x-6) = -6x+18
29) 13r+5r = 18r
30) 3x³-2x²
31) 7m+7-5m = 2m+7
32) 5z²+3z+8z² = 3z+13z²
33) (2-4n)17 = 34-68n
34) 11(4d+6) = 44d+66
35) 7m+2m+5p+4m = 13m+5p
36) 3x+7(3x+4) = 3x+21x+28 = 24x+28
37) 4(fg+3g)+5g = 4fg+12g+5g = 4fg+17g
38) (5m)²+(m+5)²= 26m²+10m+25
39) 7(a²+b)-4(a²+b) = 3(a²+b) = 3a²+b
I belive this is the answer
x³ = 27/125; and
x = 3/5.
explanation:
Reducing the voltage 3 times would result in multiplying the unknown voltage, x, by itself 3 times; this gives us
x³.
The current voltage is 27/125; this gives us the equation
x³ = 27/125.
To solve this, take the cubed root of both sides:
∛(x³) = ∛(27/125)
x = (∛27)/(∛125)
x = (∛(3*3*3))/(∛(5*5*5))
x = 3/5
Answer:
sorry I need some point
Step-by-step explanation:
