Ok, First you have to find the GCF of 120 and 90. When I got the answer I got a GCF of 30. I got 30 by multiplying all the number prime numbers 120 and 90 had, 2×3×5=30 What I did next was divide thirty by the number of cracker and also by the number of can of juice.
120÷30= 4
90÷30= 3
So as you can see there could be a maximum 30 of kid's. Each of the kids would receive 4 cans of juice and 3 packs of cheese crackers.
I hope you enjoyed my explanation. :)
Answer:
sorry dont know
Step-by-step explanation:
For this case, the first thing we must do is find the scale factor.
For this, we use one of the dimensions. We will use the width of the photo.
We have then:
![k = \frac {132} {11}\\k = 12](https://tex.z-dn.net/?f=k%20%3D%20%5Cfrac%20%7B132%7D%20%7B11%7D%5C%5Ck%20%3D%2012)
Then, we look for the value of the height of the new photo. To do this, we multiply the scale factor by the original dimension.
We have then:
![14k = 14 (12) = 168](https://tex.z-dn.net/?f=14k%20%3D%2014%20%2812%29%20%3D%20168)
Answer:
the new height will be:
d.168 inches