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inysia [295]
2 years ago
13

5. Which number lies between -5 and -6 on a number line? *

Mathematics
1 answer:
jeyben [28]2 years ago
3 0
The answer is B because -26/5= -5.2
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If runners in a long distance race were to run straight from the starting line to the finish line they would run 13 kilometers.
tia_tia [17]

5^2 +x^2 = 13^2

25 + x^2 = 169

x^2 = 144

x = sqrt(144) = 12

 they run west for 12 KM

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7 0
2 years ago
Can 171 19/32 be simplified
LenaWriter [7]

171 19/32=(171×32+19)/32=(odd number)/32.

But 32=2⁵

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4 0
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How do I go about solving (27x^3/8y^9)^5/3? And what is the role of the numerator and denominator?
MrRissso [65]
\left( \frac{27x^3}{8y^9}\right)^ \frac{5}{3}  \\\\\\ =\left( \frac{(3x)^3}{(2y^3)^3}\right)^ \frac{5}{3} \\\\\\ =  \frac{(3x)^{3 \times  \frac{5}{3} }}{(2y^3)^{3 \times  \frac{5}{3} }} \\\\\\ =\frac{(3x)^5}{(2y^3)^{5 }} \\\\\\ =\frac{243x^5}{32y^{15}}

Now, If the exponent was negative like you asked....

\left( \frac{27x^3}{8y^9}\right)^ {-\frac{5}{3}} \\\\\\ =\left( \frac{8y^9}{27x^3}\right)^ {\frac{5}{3}}\\\\\\ =\left( \frac{(2y^3)^3}{(3x)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(2y^3)^{3 \times \frac{5}{3} }}{(3x)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(2y^3)^{5 }}{(3x)^5} \\\\\\ =\frac{32y^{15}}{243x^5}

5 0
3 years ago
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