I am guessing.
I think it is the answer you have in, I am not in that grade level yet so, I may be incorrect. Take care!
The transformation from the first equation to the second one can be found by finding
a
a
,
h
h
, and
k
k
for each equation.
y
=
a
|
x
−
h
|
+
k
y
=
a
|
x
-
h
|
+
k
Factor a
1
1
out of the absolute value to make the coefficient of
x
x
equal to
1
1
.
y
=
|
x
|
y
=
|
x
|
Factor a
1
1
out of the absolute value to make the coefficient of
x
x
equal to
1
1
.
y
=
|
x
|
−
4
y
=
|
x
|
-
4
Find
a
a
,
h
h
, and
k
k
for
y
=
|
x
|
−
4
y
=
|
x
|
-
4
.
a
=
1
a
=
1
h
=
0
h
=
0
k
=
−
4
k
=
-
4
The horizontal shift depends on the value of
h
h
. When
h
>
0
h
>
0
, the horizontal shift is described as:
g
(
x
)
=
f
(
x
+
h
)
g
(
x
)
=
f
(
x
+
h
)
- The graph is shifted to the left
h
h
units.
g
(
x
)
=
f
(
x
−
h
)
g
(
x
)
=
f
(
x
-
h
)
- The graph is shifted to the right
h
h
units.
Horizontal Shift: None
Answer:
A
Step-by-step explanation:
A. The scores in order are: 10, 12, 13, 14, 14, 16, 18, 23, 24, 26. The range is 26 - 10 = 16. The mean is the sum divided by 10, which is 17. The median is between 14 & 16, which is 15. The mode is 14, since it is repeated twice.
B. The variance is calculated by subtracting each score from the mean, squaring, and adding all such squares. Then divide by the number of terms (10) to get 27.6 Take the square root to get the standard deviation, which is 5.25.
C. This is for a population, since these are all 10 games that Jason played. (If it were a sample, we would divide by 9 only)
D. The mean of 17 is higher than the median of 15 and the mode of 14. This implies a left-skewed distribution. However, the SD of 5.25 is quite high relative to the mean of 17, so the distribution is not that clearly defined yet (more data points would make it clearer).
I wrote it somewhere else where I can’t copy and paste so hope this works!
