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Komok [63]
3 years ago
10

Triangle DEF with vertices D(2, 6), E(5, 6)and F(5, 1). Write the coordinates of triangle D’E’F’ after a

Mathematics
1 answer:
Yakvenalex [24]3 years ago
8 0

Answer:

The coordinates of triangle after reflection over y-axis

 D¹( -2 ,6) , E¹( -5 ,6) , F¹ (-5,1)

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given that DEF with vertices D(2,6), E(5,6), and F(5,1)

Given that the triangle DEF reflection over the 'y' - axis then  transformed into

( x,y) → (-x,y)

Now,

D(2,6) → D¹( -2 ,6)

E(5,6)→ E¹( -5 ,6)

F(5,1)→ F¹ (-5,1)

<u><em>Final answer:-</em></u>

The coordinates of triangle after reflection over y-axis

 D¹( -2 ,6) , E¹( -5 ,6) , F¹ (-5,1)

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Which equation represents the graphed function
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\dfrac{x-x_1}{x_2-x_1} = \dfrac{y-y_1}{y_2-y_1}

Or we can make some more precise reasoning, specific to this case: the y intercept is 3. When a line is written as y=mx+q, the coefficient q is the y intercept. So, the second and third options are surely wrong.

Moreover, the slope m is the ratio between the difference bewteen the y coordinates and the x coordinates of two points on the line.

In our case, the two points differ by -1 units vertically, and 3 units horizontally. This implies that the slope is -1/3.

So, we have

y=mx+q,\quad m=-\dfrac{1}{3},\quad q=3\implies y=-\dfrac{1}{3}x+3

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A taxi charges a flat rate of R10, and an additional cost of 30 cents per kilometer. If you have
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We see that we have some nasty sqrt signs
try to use x values that yield perfect squares inside the sqrt sign like 1,4,9,16, or ones that make the inside 0


first one

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second one
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first one
y=-4+√(x+2)
so we have
(-2,-4)
(-1,-3)
(2,-2)
(7,-1)
(14,0)

second one
y=2+√(x+1)
(0,3)
(-1,2)
(3,4)
(8,5)

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Setler [38]
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h(n) = 8 * 0.9^n

b. 8 * 0.9^14 = 1.83 feet to 2 d.p.
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7 0
3 years ago
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