Answer: CFU/mL = 14200 CFU/mL
Explanation:
Microorganisms are very small and difficult to count directly. Instead, a laboratory technique is used to count CFUs (Colony Formation Units). This involves making dilutions of a microbial suspension and spreading it on thin layers of agar containing nutrients for growth in Petri dishes also called agar plates. After incubation under ideal conditions, some plates are completely covered with microbial growth; some have little or no growth; and some are covered with individual isolated "spots", which are microbial colonies. Since a colony may consist of a single organism or a group of microbes, the dots represent a CFU.
To calculate the viable count of the stock culture, you have to count the number of colonies, multiply by the dilution and the result will be the plate count in CFU.
So, the equation is:
CFU/mL = Number of colonies / (Volume trasferred to plate x dilution blank)
100 microliters = 0.1 mililiter
1/10 = 0.1 (dilution factor)
Replacing the information from the question:
CFU/mL = 142 / (0.1 mL x 0.1)
CFU/mL = 14200 CFU/mL
Answer:
A. When many species share a single ancestor
Explanation:
Answer: D. It increases the bird's chances of finding a mate.
Explanation:
As the question states, it's beautiful for the mate to see.
Answer:
<em><u>The correct option is D) The two species have a common ancestor</u></em>
Explanation:
In evolutionary studies, homologous structures can be described as structures which are similar in organisms of different species because they had a common ancestor in the past. These structures may not perform the same function but are similar because they arose from a common ancestor. Hence, the bone in a bird's wing can be homologous to a bone in a lizard leg because they have a common ancestor in the past.
Answer:
The introns of protein-encoding nuclear genes of higher eukaryotes almost invariably begin (5') with GT and end (3') with AG. In addition, the 3'subterminal A in the “TACTAAC box” is completely conserved; this A is involved in bond formation during intron excision.