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kykrilka [37]
3 years ago
7

For what values of x is the rational expression below undefined?

Mathematics
1 answer:
EastWind [94]3 years ago
5 0
(x-4)/(3)(x+5)(x-5)

In order for the rational expression to be undefined, the denominator must be equal to 0.

Thus, set 3(x+5)9(x-5)=0

x=5 and -5 
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What is the domain (in interval notation) of the following functions?
alexgriva [62]
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3.\\f(x)=\frac{\sqrt{x}}{x^2-5x}\\\\D:x\geq0\ \wedge\ x^2-5x\neq0\to x\geq0\ \wedge\ x(x-5)\neq0\\\\\to x\geq0\ \wedge\ x\neq0\ \wedge\ x\neq5\to x\in\mathbb{R^+}\ \backslash\ \{5\}\\\\4.\\g(x)=\frac{\sqrt{x}+5}{x^2-x-20}\\\\D:x\geq0\ \wedge\ x^2-x-20\neq0\to x\geq0\ \wedge\ (x+4)(x-5)\neq0\\\\\to x\geq0\ \wedge\ x\neq-4\ \wedge\ x\neq5\to x\in\left

5.\\h(x)=\frac{3}{x^2+1}\\\\D:x^2+1\neq0\to x^2\neq-1\to x\in\mathbb{R}\\\\6.\\f(x)=\frac{\sqrt{x-2}}{x+1}\\\\D:x-2\geq0\ \wedge\ x+1\neq0\to x\geq2\ \wedge\ x\neq-1\to x\in\left

7.\\g(x)=\frac{x^2}{3x^2-x-2}\\\\D:3x^2-x-2\neq0\to (3x+2)(x-1)\neq0\to x\neq-\frac{2}{3}\ \wedge\ x\neq1\\\\\to x\in\mathbb{R}\ \backslash\ \{-\frac{2}{3};\ 1\}\\\\8.\\h(x)=3(x-4)^2-7\\\\D:x\in\mathbb{R}
4 0
3 years ago
Select the values that makes the inequality -w≥ 7 true. Then write an equivalent inequality, in terms of w
Veseljchak [2.6K]

Answer:

B

Step-by-step explanation:

Its becuase I am right, here is the among us code btw QRTVRF

8 0
3 years ago
For ten school days the numbers of bikes parked at a school bike rack are 10,12,8,11,13,9,2,1,9, and 12​
kumpel [21]

0

Step-by-step explanation:

for this question is not even possible

6 0
3 years ago
I don’t understand this
mylen [45]
To solve for an unknown number, you have to keep isolating it till it is all alone:
A=P(1+rt)
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7 0
3 years ago
Mr.rodriguez invests half money in land a tenth in stocks and a twentieth in bonds he puts the remaining 35,000 in his savings a
Elena-2011 [213]

Answer:  $100,000

<u>Step-by-step explanation:</u>

   Land  +  Stocks  +  Bonds  +  Savings  =  100%

    \dfrac{1}{2}x    +    0.1x     +    \dfrac{1}{20}x       +  35,000   =  1.00x  

=  0.5x   +     0.1x   +     0.05x  +  35,000  =  1.00x

=                                    0.65x  +  35,000  =  1.00x

                                                     35,000  =  0.35x

                                                     \dfrac{35,000}{0.35}=\dfrac{0.35x}{0.35}

                                                    100,000  =  x  

3 0
3 years ago
Read 2 more answers
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