Answer:
(a) Sample Space

(b) PMF

(c) CDF

Step-by-step explanation:
Solving (a): The sample space
From the question, we understand that at most 3 cars will be repaired.
This implies that, the number of cars will be 0, 1, 2 or 3
So, the sample space is:

Solving (b): The PMF
From the question, we have:



can be represented as:
![P(1) + P(2) = 0.5[P(0) + P(3)]](https://tex.z-dn.net/?f=P%281%29%20%2B%20P%282%29%20%3D%200.5%5BP%280%29%20%2B%20P%283%29%5D)
Substitute
and 
![P(1) + P(1) = 0.5[P(0) + P(0)]](https://tex.z-dn.net/?f=P%281%29%20%2B%20P%281%29%20%3D%200.5%5BP%280%29%20%2B%20P%280%29%5D)
![2P(1) = 0.5[2P(0)]](https://tex.z-dn.net/?f=2P%281%29%20%3D%200.5%5B2P%280%29%5D)


Also note that:

Substitute
and 


Substitute 



Solve for P(1)

To calculate others, we have:






Hence, the PMF is:

<em>See attachment (1) for histogram</em>
Solving (c): The CDF ; F(x)
This is calculated as:

For x = 0;
We have:


For x = 1



For x = 2



For x = 3



Hence, the CDF is:

<em>See attachment (2) for histogram</em>
Answer:
it would be a 60%
Step-by-step explanation:
Divide 84 by 140, and you get .6
Hope this helps!!
Answer:
The expected amount of pap smears that must be inspected before the first abnormal one is found is 50
Step-by-step explanation:
If 2 percent of all pap smears show signs of abnormality, then the probability that a pap smear is abnormal is 0.02.
Let X be the amount of pap smears needed before the first abnormal case is found. X has geometric ditribution with parameter p = 0.02. The mean of X, in other words, the expected amount of cases that must be inspected before the first abnormal one appears, is 1/p = 1/0.02 = 50.
Answer:
Step-by-step explanation:
A) Samantha's answer is incorrect because 15r ----> 15*r. So when 15 goes to other side, multiplication will change to division (not subtraction)
15r = 105
divide both sides by 15

B)This equation has only one solution.