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Debora [2.8K]
2 years ago
10

The graph of the equation y= ax^2 , where a is > O , is shown below, If a is multiplied by 1/2 , the graph of the new equatio

n is
a
A widet and opens downward
B
Wider and opens upward
C
Narrower and opend downward
D
Narrower and opend upward
Mathematics
1 answer:
GenaCL600 [577]2 years ago
5 0

Answer:

wider and opens downward

Step-by-step explanation:

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!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Natasha_Volkova [10]

Answer:   1. 447

                2. 572

                3. 257

               

Step-by-step explanation:

3 0
2 years ago
Points F,G, and H are collinear such that FG:FH=2/3.If a directed line segment begins at F(-3,2) and ends at H (-3,7), find the
Nana76 [90]
We consider the x- and y-coordinates separately. Let the coordinates of G be (x, y). Now considering the x-coordinates:
FG/FH = (x - (-3)) / (-3 - (-3)) = 2/3
x + 3 = (2/3)(6)
x = 1
For the y-coordinates:
FG/FH = (y - 2) / (7 - 2) = 2/3
y - 2 = (2/3)(5)
y = 16/3
Therefore the coordinates of G are (1, 16/3).
8 0
3 years ago
Change 3500 ml to litres.​
Neko [114]

Answer: 3.5L

Step-by-step explanation:

1000 Ml = 1L

3500 Ml = 3.5L

3 0
2 years ago
Read 2 more answers
The measures of the base angles of an isosceles triangle are 3x 5 and 5x - 25. The measure of the vertex angle is 6x - 10. Find
lukranit [14]

Answer: The measure of the vertex angle = 80°

Step-by-step explanation:

Angle sum property of triangle : The sum of the measures of the angles for any triangle is 180 degrees.

So,

3x+ 5 + 5x-25+6x-10= 180\\\\\Rightarrow\ 14x-30=180\\\\\Rightarrow\ 14x= 210\\\\\Rightarrow x=\dfrac{210}{14}=15'

Then, vertex angle = 6(15)-10=90-10= 80

Hence, The measure of the vertex angle = 80°

5 0
2 years ago
4 x 10^6 is how many times large then 1 x 10^4
Molodets [167]

Answer:

<h2>400</h2>

Step-by-step explanation:

4\times10^6\text{ is how many times large than}\ 1 \times 10^4?\\\\\dfrac{4\times10^6}{1\times10^4}=\dfrac{4}{1}\times\dfrac{10^6}{10^4}=4\times10^{6-4}=4\times10^2=4\times100=400

4 0
3 years ago
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