B
the probability of an event ( A<span> ), given that another ( </span>B<span> ) has already occurred.
</span>
(6(x^2-1))*((6x-1)/(6(x+1))
(6((x+1)(x-1)))((6x-1)/(6(x+1))
(6(x-1))*(6x-1)/(6)
(x-1)(6x-1)
6x^2-x-6x+1
6x^2-7x+1
Answer:C
Step-by-step explanation:
Answer:
108 children were drinking apple juice. $432 were spent on pizza.
Step-by-step explanation:
How many children were drinking apple juice:
567 - 323 - 136 = 108
How many children were eating pizza:
108 * 2 = 216
How much was spent on pizza:
216 * $2 = $432
Answer:
2.6666
Step-by-step explanation:
hypotenuse is c^2 so you square 4 to get 16 and then you divide it by 6 to 2.666 so that is the answer for the other leg
