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3 years ago

You give an 18% tip for a meal. What expression represents the total cost with tip?

Mathematics

1 answer:

vodomira [7]3 years ago

5 0

Answer:

multiply the cost by 0.18 to get the tip amount or multiply the cost by 1.18 to get the total including tip.

Step-by-step explanation:

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Helllp pleaseeee!!!! Solve for x. 2^4x=8^3x-10

igomit [66]

Answer:

Step-by-step explanation:

Let's solve your equation step-by-step.

(24)(x)=(83)(x)−10

Step 1: Simplify both sides of the equation.

(24)(x)=(83)(x)−10

16x=512x+−10

16x=512x−10

Step 2: Subtract 512x from both sides.

16x−512x=512x−10−512x

−496x=−10

Step 3: Divide both sides by -496.

−496x

−496

−10

−496

248

4 0

3 years ago

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Marie plays the state lottery. During the lotteries in June, she lost $10, won $20, lost $8, lost $12, and won $25. What was the

xenn [34]

The answer to your question is Marie won 15$

7 0

3 years ago

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-4(4v-u-6) solve using distributive property

GarryVolchara [31]

Answer:

Step-by-step explanation:

-4 ( 4v - u - 6 )

You will multiply -4 with everything in the parentheses.

-16v + 4u + 24

4 0

4 years ago

5) I 6 50° 16x + 2 B) 9 A) -10 C) 4 D) 8

dalvyx [7]

Answer:

c is answer

Step-by-step explanation:

c is ans because it is simple c only serves the need of questions and satisfy it

8 0

3 years ago

Read 2 more answers

1. A weight of 18,000 lb is supported on a rectangular base plate that is 9 in. wide and 2 ft long. The base plate rests on a co

slega [8]

Answer:

a) $83.3\ lb/in^2$

b) $12000\ lb/ft^2$

Step-by-step explanation:

Given : A weight of 18,000 lb is supported on a rectangular base plate that is 9 in. wide and 2 ft long. The base plate rests on a concrete slab.

To find : Determine the stress that the base plate exerts on the concrete slab. Express your answer in units of (a) lb/in². and (b) lb/ft².

Solution :

a) A rectangular base plate that is 9 in. wide and 2 ft long.

Converting ft into inches,

1 feet = 12 inch

2 feet = 2×12= 24 inch

The area of the rectangular base is $A=l\times b$

$A_1=24\times 9$

$A_1=216\ in^2$

The weight is W=18,000 lb.

The stress that the base plate exerts on the concrete slab is given by,

$S=\frac{W}{A_1}$

$S=\frac{18000\ lb}{216\ in^2}$

$S=83.3\ lb/in^2$

b) A rectangular base plate that is 9 in. wide and 2 ft long.

Converting inches into ft,

1 inch = $\frac{1}{12}\ ft$

9 feet = $\frac{9}{12}=0.75\ ft$

The area of the rectangular base is $A=l\times b$

$A_2=2\times 0.75$

$A_2=1.5\ ft^2$

The weight is W=18,000 lb.

The stress that the base plate exerts on the concrete slab is given by,

$S=\frac{W}{A_2}$

$S=\frac{18000\ lb}{1.5\ ft^2}$

$S=12000\ lb/ft^2$

5 0

3 years ago