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Ainat [17]
3 years ago
5

Given that the measure of ∠x is 110°, and the measure of ∠y is 59°, find the measure of ∠z.

Mathematics
1 answer:
ch4aika [34]3 years ago
6 0
180-110=70
180-(70+59)=180-129=51
Z=51 im p sure
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An arch over a doorway is an arc that is 90 centimeters wide and 30 centimeters high. You are curious about the size of the enti
krek1111 [17]

Answer:

The length of the arc = 114.66\,cm

And the length of the full circle: 306.3\, cm

Step-by-step explanation:

To solve this problem we will be analyzing aright angle triangle that is formed when drawing the appropriate radius associated with the arc and the chord of a segment of circumference as depicted by the triangle shaded in yellow in the attached image.

Notice that the information given in this problem can be represented by:

1) the 90 cm width of the arc with the value of 2x (drawn in orange) in the drawing

2) the 30 cm of the arc's height with the value of y (drawn in green) in the drawing

In order to use the Pythagorean theorem in the little yellow triangle, notice that the hypotenuse is given by the radius R of the circle, and the two legs of the right angle triangle are given by "x" and "R-y"

So the Pythagoras theorem becomes:

R^2=x^2+(R-y)^2\\R^2=x^2+R^2-2Ry+y^2\\0=x^2-2Ry+y^2\\2Ry=x^2+y^2\\R=\frac{x^2+y^2}{2y}

Therefore, in our case, where x=45 cm, and y=30 cm, we have:

R=\frac{x^2+y^2}{2y} \\R=\frac{45^2+30^2}{60}\,cm \\R=48.75\, cm

Now, with the radius, we can calculate the length of the arc of circle if we know the subtended angle in radians:

length of arc = R \,\theta

The angle \theta subtended by the arc can be obtained by doubling the angle with vertex at the circle's center in our yellow right angle triangle. This is done via the sine function:

\theta=2\,arcsin(x/R)\\\theta=2\,arcsin(45/48.75)\\\theta=2.352\,radians

Therefore, length of the arc = R \,\theta=48.75\,cm\,*\,2.352=114.66\,cm

And the length of the full circle: 2\,\pi \, R =2\,\pi\,48.75\,cm = 306.3\, cm

3 0
3 years ago
Determine algebraically the zeros of f(x)=3x^3+21x^2+36x
Mashcka [7]

Answer:

The zeros of the given polynomial function f(x) are -3,0,-4

Step-by-step explanation:

Given polynomial is f(x)=3x^3+21x^2+36x

To find the zeros of the given polynomial:

First equate the polynomial function f(x) to zero

That is f(x)=3x^3+21x^2+36x=0

By synthetic division we can solve it

-3_| 3      21       36     0

      0       -9      -36    0

   _____________________

      3      12        0        0

      Therefore x+3 is a factor

    That is x=-3 is a zero

    3x^2+12x=0

    3x(x+4)=0

    3x=0 or x+4=0

    Therefore x=0 or x=-4

    Therefore the zeros are -3,0,-4

6 0
3 years ago
I need help please its really easy
AleksAgata [21]
Line DF I think sry if it’s wrong!
6 0
3 years ago
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Easy math for smart people problem: 3(b+1)=4b-1
irakobra [83]

Answer:

b=4

Step-by-step explanation:

3b-4b+3+1=0

-b=-4

b=4

4 0
3 years ago
Read 2 more answers
How does a graph show a proportional relationship
grin007 [14]
The proportional relationship is found in the slope which is the change in y over the change in x (rise over run):

Δy/<span>Δx
</span>
5 0
3 years ago
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