Answer:
![a > \frac{22}{21}](https://tex.z-dn.net/?f=a%20%3E%20%5Cfrac%7B22%7D%7B21%7D)
Step-by-step explanation:
Given the inequality function
, to write the inequality in interval notation, we need to first get the solution to the inequality as shown;
![\frac{14a}{11}>\frac{4}{3}\\cross\ multiply\\14a \times 3 > 11 \times 4\\42a >44\\divide \ both \ sides \ by \ 42\\\frac{42a}{42} > \frac{44}{42}\\ a>\frac{22}{21}](https://tex.z-dn.net/?f=%5Cfrac%7B14a%7D%7B11%7D%3E%5Cfrac%7B4%7D%7B3%7D%5C%5Ccross%5C%20multiply%5C%5C14a%20%5Ctimes%203%20%3E%2011%20%5Ctimes%204%5C%5C42a%20%3E44%5C%5Cdivide%20%5C%20both%20%5C%20sides%20%5C%20by%20%5C%2042%5C%5C%5Cfrac%7B42a%7D%7B42%7D%20%3E%20%5Cfrac%7B44%7D%7B42%7D%5C%5C%20a%3E%5Cfrac%7B22%7D%7B21%7D)
Hence the expression in interval notation is ![a > \frac{22}{21}](https://tex.z-dn.net/?f=a%20%3E%20%5Cfrac%7B22%7D%7B21%7D)
Answer:
Step-by-step explanation:
I think it is C
160 = 2 x 2 x 2 x 2 x 2 x 5 = 2^5 x 5
243 = 3 x 3 x 3 x 3 x 3 = 3^5
So
(160 * 243)^1/5
= 5th root of (160 * 243)
= 5th root of (2^5 * 5 * 3^5)
= 2 * 3 * (5th root of 5)
= 6 * (5th root of 5)
Answer is D. 6 * (5th root of 5)
Answer:
s = 32
Step-by-step explanation:
First distribute the -5:
-5s + 150 = -10
Add 10 to both sides
-5s = 160
Divide by -5 on both sides
s = 32
Answer:
![\cos^{-1}(\frac{6.3}{9.8})](https://tex.z-dn.net/?f=%5Ccos%5E%7B-1%7D%28%5Cfrac%7B6.3%7D%7B9.8%7D%29)
![\sin^{-1}(\frac{7.5}{9.8})](https://tex.z-dn.net/?f=%5Csin%5E%7B-1%7D%28%5Cfrac%7B7.5%7D%7B9.8%7D%29)
Step-by-step explanation:
Recall the mnemonics SOH-CAH-TOA
The sine ratio is the length of the opposite side expressed over the hypotenuse.
![\sin m\angle ABC=\frac{7.5}{9.8}](https://tex.z-dn.net/?f=%5Csin%20m%5Cangle%20ABC%3D%5Cfrac%7B7.5%7D%7B9.8%7D)
Take the sine inverse of both sides to get;
![m\angle ABC=\sin^{-1}(\frac{7.5}{9.8})](https://tex.z-dn.net/?f=m%5Cangle%20ABC%3D%5Csin%5E%7B-1%7D%28%5Cfrac%7B7.5%7D%7B9.8%7D%29)
The cosine ratio is the length of the adjacent side expressed over the hypotenuse.
![\cos m\angle ABC=\frac{6.3}{9.8}](https://tex.z-dn.net/?f=%5Ccos%20m%5Cangle%20ABC%3D%5Cfrac%7B6.3%7D%7B9.8%7D)
Take the cosine inverse of both sides to get;
![m\angle ABC=\cos^{-1}(\frac{6.3}{9.8})](https://tex.z-dn.net/?f=m%5Cangle%20ABC%3D%5Ccos%5E%7B-1%7D%28%5Cfrac%7B6.3%7D%7B9.8%7D%29)