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3 years ago

Calculate the height of the cylinder shown.

Mathematics

2 answers:

bekas [8.4K]3 years ago

7 0

Answer:

37.3

Step-by-step explanation:

If you want to solve it.

Cylineder Formula: Volume = π(radius)²(height)

Isolate height by diving πr² on both sides.

height = (volume/πr²)

height = (300/π(1.6^2))

olga_2 [115]3 years ago

4 0

Answer:

h = 36.2 cm

Step-by-step explanation:

lets make it short and simple

vol of cylinder + volume of hemisphere = 300 cu.cm.

Vc + Vh = 300 --- eq.1

cylinder radius = 1.6 cm.

since it says NOT TO SCALE

let the radius of hemisphere is the same as cylinder.

vol of cylinder = πr²h

vol of hemisphere = 2/3 πr³

using eq.1

πr²h + 2/3 πr³ = 300

π (1.6²) h + 2/3 π (1.6³) = 300

h = 36.2 cm

check:

Vc + Vh = 300

π (1.6²) 36.2 + 2/3 π (1.6³) = 300

300 cu.cm = 300 cu.cm. ----OK

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Check the picture below.

so let's find the lengths of those two sides in red, since are the length and width of the rectangle.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-3}~,~\stackrel{y_2}{6})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d = \sqrt{[-3-(-6)]^2+[6-3]^2}\implies d=\sqrt{(-3+6)^2+(6-3)^2} \\\\\\ d=\sqrt{9+9}\implies \boxed{d=\sqrt{18}} \\\\[-0.35em] ~\dotfill$

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-1})~\hfill d=\sqrt{[-2-(-6)]^2+[-1-3]^2} \\\\\\ d=\sqrt{(-2+6)^2+(-1-3)^2}\implies d=\sqrt{16+16}\implies \boxed{d=\sqrt{32}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of the rectangle}}{(\sqrt{18})(\sqrt{32})}\implies \sqrt{18\cdot 32}\implies \sqrt{576}\implies 24$