Answer:
Step-by-step explanation:
See attachment.
The change from x to (x-4) moved the function to the right by 4. The - 5 moved it down by 5 (as measured from the crossover/inflection point.
Answer:
The rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station is 372 mi/h.
Step-by-step explanation:
Given information:
A plane flying horizontally at an altitude of "1" mi and a speed of "430" mi/h passes directly over a radar station.


We need to find the rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station.

According to Pythagoras


.... (1)
Put z=1 and y=2, to find the value of x.




Taking square root both sides.

Differentiate equation (1) with respect to t.

Divide both sides by 2.

Put
, y=2,
in the above equation.

Divide both sides by 2.



Therefore the rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station is 372 mi/h.
Answer:
Intersept is (4.55,0)
Step-by-step explanation:
Answer:
g(x) = 1/2x^2
Step-by-step explanation:
I hope this helps