Answer:
The percentage of the population that is heterozygous for this trait is 48%
Explanation:
They are two alleles, the phenylthiocarbamide tasters (PTC) and the non phenylthiocarbamide tasters (non PTC). PTC testers are dominant and non PTC tasters are recessive.
let the frequency of the dominant allele(A) be p
and the frequency of the recessive allele(a) be q
We are told that 64 percent of people living in a remote, isolated mountain village can taste phenylthiocarbamide (PTC) and must, therefore, have at least one copy of the dominant PTC taster allele (that is AA and Aa)
Frequency of AA = p², Frequency of Aa = 2pq and Frequency of aa = q²
Therefore p² + 2pq = 64% = 0.64
According to Hardy–Weinberg:
p² + 2pq + q² = 1 and
p + q = 1
Since p² + 2pq = 0.64
∴ 0.64 + q² = 1
q² = 1 - 0.64 = 0.36
q = √0.36 = 0.6
Since p + q = 1
p = 1 - q = 1 - 0.6 = 0.4
The frequency of heterozygous = 2pq = 2 × 0.4 × 0.6 = 0.48
Therefore the percentage of the population that is heterozygous for this trait is 48%
<span>About 2 weeks.
Since the species isn't mentioned, I will assume human.
Definitions
Colostrum: This is the fluid expressed by the breasts just prior to and for a few days after giving birth. It contains a much higher concentration of nutrients in an easier to digest form than regular breast milk. This type of breast milk will be produced for 2 to 4 days after giving birth.
Transitional Milk: This is a thick creamy milk that contains more fat, lactose, vitamins and calories than colostrum. It starts within 4 days of giving birth and lasts approximately 2 weeks.
Mature Milk: This is a thinner milk that's about 90% water and 10% nutrients. It starts about 2 weeks after giving birth.
So the answer is about 2 weeks.</span>
Comparative and experimental investigations are two of three scientific investigations, the other is descriptive investigations.
--hope this helps--
A, a , b, a is ur answers
That organism is called a carrier
