X and y are the numbers
x>y
diffference is 42
x-y=42
larger is 3 less than 6 times smaller
x=-3+6y
subsitute -3+6y for x
x-y=42
-3+6y-y=42
-3+5y=42
add3 to both sides
5y=45
divide both sides by 5
y=9
sub back
x=-3+6y
x=-3+6(9)
x=-3+54
x=51
the numbers are 51 and 9
The question here is how long does it take for a falling
person to reach the 90% of this terminal velocity. The computation is:
The terminal velocity vt fulfills v'=0. Therefore vt=g/c,
and so c=g/vt = 10/(100*1000/3600) = 36,000/100,000... /s. Incorporating the
differential equation shows that the time needed to reach velocity v is
t= ln [g / (g-c*v)] / c.
With v=.9 vt =.9 g/c,
t = ln [10] /c = 6.4 sec.
6:10 is 47 mins before 6:57!!
When dividing same numbers with different exponents (they’re both 10 so this works different than if they were different numbers) you subtract the top exponent by the bottom exponent. So 15-4=11 ultimately making the solution 10^11. Hope this helps :)
