1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
melomori [17]
3 years ago
13

Determine whether the source given below has the potential to create a bias in a statistical study.A certain medical organizatio

n tends to oppose the use of meat and dairy products in our​ diets, and that organization has received hundreds of thousands of dollars in funding from an animal rights foundation.
Mathematics
1 answer:
Tpy6a [65]3 years ago
7 0

Answer:

There appears to be statistical bias.

Step-by-step explanation:

There is a likelihood of potential bias in the experiment. This is is because the results can be manipulated so that they can be in line with the organization's objectives and of the funders.

Only verified and quantified surveys are able to provide statistically unbiased results.

You might be interested in
An equation for the depreciation of a car is given by y = A(1 – r)t , where y = current value of the car, A = original cost, r =
Mamont248 [21]
<h2>The car is about 6.6 years old.</h2>

Step-by-step explanation:

Given : An equation for the depreciation of a car is given by y = A(1-r)^t, where y = current value of the car, A = original cost, r = rate of depreciation, and t = time, in years. The value of a car is half what it originally cost. The rate of depreciation is 10%.

To find : Approximately how old is the car?

Solution :

The value of a car is half what it originally cost i.e. y=\frac{1}{2} A

The rate of depreciation is 10% i.e. r=10%=0.1

Substitute in the equation, y = A(1-r)^t

\frac{1}{2} A= A(1-0.1)^t

\frac{1}{2}= (0.9)^t

Taking log both side,

\log(\frac{1}{2})=t\log (0.9)

t=\frac{\log(\frac{1}{2})}{\log (0.9)}

t=6.57

t\approx 6.6

Therefore, the car is about 6.6 years old.

3 0
3 years ago
Read 2 more answers
Solve for q. 3(q-7)=26 q=
TEA [102]

Answer:

3(q - 7) = 27

3q - 21 = 27

3q = 27 +21 = 48

q  = \frac{48}{3}  = 16

6 0
4 years ago
Read 2 more answers
If 6 is added to 2 times a certain number, the result is 14. Find the number. Please answer!!
ipn [44]

Answer:

4

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
The ages
Zepler [3.9K]

Answer:

Mean: 46 Median: 45 Mode: 45

Step-by-step explanation:

Mean: 41+45+39+56+48+45+42+34+47+62+35+58 = 552 then, 552/12 = 46

Median: Put numbers in order from least to greatest and cross one out on each side until you get to the middle number. 45 and 45 were the last two numbers to be crossed out, the middle of those would simply be 45!

Mode: 45 appears twice while the rest of the numbers only appeared once.

I hope this helped, good luck! :)

7 0
3 years ago
Read 2 more answers
How do you find out what it represents?
pochemuha

Answer:

the answer is your second choice.

Step-by-step explanation:

y=3x+2

y=-x+2

(i checked with an inequalities calculator)

7 0
3 years ago
Other questions:
  • PLZ HELP! A train averages a speed of 90 miles per hour across the plains and 37.5 miles per hour through the mountains. If a tr
    8·1 answer
  • Tina is saving to buy a notebook computer. She has two options. The first option is to put S200 away initially and save $10 ever
    9·1 answer
  • 7.9y-2-3.2y-10=2.8+y
    11·1 answer
  • Please Help! Which statement best demonstrates why the following is a non-example of a polynomial?
    6·2 answers
  • I need help... I honestly don’t know.
    8·2 answers
  • Find the square root of 167281 by division method
    12·1 answer
  • 1/5 x = 20 solve for x
    13·1 answer
  • Triangle FGH is an equilateral triangle.FH=6x+1,FG=3x+10,and GH=9x-8
    11·1 answer
  • Find the maximum value on (0, infinity) for f(x)=7x-2xlnx
    6·1 answer
  • A circle has a diameter of 26 feet. Find its circumference and area.
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!