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2 years ago

11

1) Tyheem mowed 6 lawns in 4 hours. Assuming he maintains a constant speed, how many lawns can be mowed in 6 hours? Show your wo

rk. QUICKKK

1 answer:

Irina-Kira [14]2 years ago

6 0

He can mow 9 lawns

6/4 = x/6

6/4=1.5

1.5 x 6 = 9

9 lawns can be mowed by Tyheem in 6 hours

Please give me full points, heart, and Brainliest comment.

You might be interested in

Answer Please---Due today!!!

Angelina_Jolie [31]

Answer:

14/44 or 7/22

because 44 is the total and the total number of latin cds are 14

so 14/44 simplified would be 7/22

hope it helped

Step-by-step explanation:

Please rate and mark as brainliest

Thank you and have a good day

5 0

1 year ago

Read 2 more answers

rosijanka [135]

<u>Answer:</u>

$6^{10}$

<u>Step-by-step explanation:</u>

We can use the following rule of surds to solve the problem:

$\boxed{a^m \times a^n = a^{m + n}}$ ,

which means that when multiplying two numbers with the same bases, we can simply add their powers while keeping the base the same.

Applying this rule:

$6^2 \times 6^8$

⇒ $6^{2 + 8}$

⇒ $\bf 6^{10}$

8 0

1 year ago

Find T5(x) : Taylor polynomial of degree 5 of the function f(x)=cos(x) at a=0 . (You need to enter function.) T5(x)= Find all va

Burka [1]

Answer:

$\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}$

The polynomial is an approximation with an error less than or equals to <em>0.002652</em> for x in the interval

[-1.113826815, 1.113826815]

Step-by-step explanation:

According to Taylor's theorem

$\bf f(x)=f(0)+f'(0)x+f''(0)\displaystyle\frac{x^2}{2}+f^{(3)}(0)\displaystyle\frac{x^3}{3!}+f^{(4)}(0)\displaystyle\frac{x^4}{4!}+f^{(5)}(0)\displaystyle\frac{x^5}{5!}+R_6(x)$

with

$\bf R_6(x)=f^{(6)}(c)\displaystyle\frac{x^6}{6!}$

for some c in the interval (-x, x)

In the particular case f

<em>f(x)=cos(x) </em>

<em> </em>

we have

$\bf f'(x)=-sin(x)\\f''(x)=-cos(x)\\f^{(3)}(x)=sin(x)\\f^{(4)}(x)=cos(x)\\f^{(5)}(x)=-sin(x)\\f^{(6)}(x)=-cos(x)$

therefore

$\bf f'(x)=-sin(0)=0\\f''(0)=-cos(0)=-1\\f^{(3)}(0)=sin(0)=0\\f^{(4)}(0)=cos(0)=1\\f^{(5)}(0)=-sin(0)=0$

and the polynomial approximation of T5(x) of cos(x) would be

$\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}$

In order to find all the values of x for which this approximation is within 0.002652 of the right answer, we notice that

$\bf R_6(x)=-cos(c)\displaystyle\frac{x^6}{6!}$

for some c in (-x,x). So

$\bf |R_6(x)|\leq|\displaystyle\frac{x^6}{6!}|=\displaystyle\frac{|x|^6}{6!}$

and we must find the values of x for which

$\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652$

Working this inequality out, we find

$\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652\Rightarrow |x|^6\leq1.90944\Rightarrow\\\\\Rightarrow |x|\leq\sqrt[6]{1.90944}\Rightarrow |x|\leq1.113826815$

Therefore the polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval

[-1.113826815, 1.113826815]

8 0

2 years ago

Which names the tiling

horrorfan [7]

<h3>Answer:</h3>

4, 8, 8

<h3>Step-by-step explanation:</h3>

At each node, three faces meet. One is square (4 sides); the other two are octagons (8 sides). Hence the tiling can be named with three numbers: 4, 8, 8.

7 0

2 years ago

Read 2 more answers

60 points !! i'll mark brainliest as well . don't scam or i'll report thanksss :)

sp2606 [1]

Answer:

2, 6, 28, 358.01

Step-by-step explanation:

We have to find the fractions of whole numbers.

Number 1:

$\frac{1}{5}$ of 10 = $\frac{1}{5} \times (2 \times 5) = 2$ (Answer)

Number 2:

$\frac{2}{3}$ of 9 = $\frac{2}{3} \times (3 \times 3) = 2 \times 3 = 6$ (Answer)

Number 3:

$\frac{7}{8}$ of 32 = $\frac{7}{8} \times (4 \times 8) = 7 \times 4 = 28$ (Answer)

Number 4:

$3 \times 10^{2} + 5 \times 10^{1} + 8 \times 10^{0} + 1 \times \frac{1}{10^{2} }$

= $3 \times 100 + 5 \times 10 + 8 \times 1 + \frac{1}{100}$ {Since $a^{0} = 1$ }

= 300 + 50 + 8 + 0.01

= 358.01 (Answer)

4 0

2 years ago