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3 years ago

Help you yall thank you

Mathematics

2 answers:

Tresset [83]3 years ago

7 0

A,C,D I’m pretty sure

IrinaVladis [17]3 years ago

7 0

The answer is A,C,D :)

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(ONLY TWO CAPITAL LETTERS) PLEASE ANSWER CORRECTLY!!!!!! WILL MARK BRIANLIEST!!!!!!!! URGENT

lesantik [10]

Answer:

HN congruent to NL

Step-by-step explanation:

They have a line crossing both of them, signifiying congruence.

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3 years ago

Find the volume of the cone show below:

antiseptic1488 [7]

Formula for the volume not a cone=πr2H. π=3.14. R=12×2=24. H=16. 3.14×24=75.36. 75.36×16=1205.76. ANSWER: 1205.76

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3 years ago

7% of $582 is how much?

ipn [44]

Answer:

$541.26

Step-by-step explanation:

Please let me know if this helps

Plz mark B R A I N L I E S T

5 0

3 years ago

Read 2 more answers

When the sum of \, 528 \, and three times a positive number is subtracted from the square of the number, the result is \, 120. F

aleksandr82 [10.1K]

Let $x$ be the unknown number. So, three times that number means $3x$ , and the square of the number is $x^2$

We have to sum 528 and three times the number, so we have $528+3x$

Then, we have to subtract this number from $x^2$ , so we have

$x^2-(3x+528)$

The result is 120, so the equation is

$x^2 - 3x - 528 = 120 \iff x^2 - 3x - 648 = 0$

This is a quadratic equation, i.e. an equation like $ax^2+bx+c=0$ . These equation can be solved - assuming they have a solution - with the following formula

$x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

If you plug the values from your equation, you have

$x_{1,2} = \dfrac{3\pm\sqrt{9-4\cdot(-648)}}{2} = \dfrac{3\pm\sqrt{9+2592}}{2} = \dfrac{3\pm\sqrt{2601}}{2} = \dfrac{3\pm51}{2}$

So, the two solutions would be

$x = \dfrac{3+51}{2} = \dfrac{54}{2} = 27$

$x = \dfrac{3-51}{2} = \dfrac{-48}{2} = -24$

But we know that x is positive, so we only accept the solution $x = 27$

6 0

3 years ago

I really need help with this math problem.

Art [367]

Answer D.

$(36\dfrac{3}{4} +36\dfrac{3}{8} +37\dfrac{1}{2} +z):4=36\dfrac{5}{8}\\\\\\36\dfrac{6}{8} +36\dfrac{3}{8} +37\dfrac{4}{8} +z=4\cdot36\dfrac{5}{8}\\\\\\36\dfrac{6}{8} +36\dfrac{3}{8} +37\dfrac{4}{8} +z=4\cdot36\dfrac{5}{8}\\\\\\109\dfrac{13}{8}+z=4\cdot36+4\cdot\dfrac{5}{8}\\\\\\110\dfrac{5}{8}+z=144+\dfrac{20}{8} \\\\\\z=144+\dfrac{20}{8} -110-\dfrac{5}{8}\\\\\\z=34+\dfrac{15}{8}\\\\\\z=34+1\dfrac{7}{8}\\\\\\z=35\dfrac{7}{8}$

3 0

3 years ago