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3 years ago

Find the area of the combined rectangles. Please help me

Mathematics

1 answer:

amid [387]3 years ago

3 0

Answer:

8: 190 yd , 9: 30 m, 10: 92 ft

Step-by-step explanation:

for 8, you can spit it up pretty simply. find 10x18 which is 180 and then 5x2 which is 10 so 8 is 190.

for 9, 2x8=18 for the top portion and for the sides 3x2=6, so twelve. Combined its 30m.

for 10, 10x8=80, then 6x2=12. so 92 ft combined.

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6 = 2(1+2) =<br> Somebody help me answer this please

Kitty [74]

Answer:

Step-by-step explanation:

6 = 2(1+2)

Use distributive property (Multiply 2 and 1. Then multiply 2 and 2)

6 = 2+4

Now add

6=6

This means the statement is true

3 0

3 years ago

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Use matrices to solve the system of equations if possible. Use Gaussian elimination with back substitution or gauss Jordan elimi

CaHeK987 [17]

In matrix form, the system is given by

$\begin{bmatrix} -1 & 1 & -1 \\ 2 & -1 & 1 \\ 3 & 2 & 1 \end{bmatrix} \begin{bmatrix} x \\ y \\ z \end{bmatrix} = \begin{bmatrix} -20 \\ 29 \\ 29 \end{bmatrix}$

I'll use G-J elimination. Consider the augmented matrix

$\left[ \begin{array}{ccc|c} -1 & 1 & -1 & -20 \\ 2 & -1 & 1 & 29 \\ 3 & 2 & 1 & 29 \end{array} \right]$

• Multiply through row 1 by -1.

$\left[ \begin{array}{ccc|c} 1 & -1 & 1 & 20 \\ 2 & -1 & 1 & 29 \\ 3 & 2 & 1 & 29 \end{array} \right]$

• Eliminate the entries in the first column of the second and third rows. Combine -2 (row 1) with row 2, and -3 (row 1) with row 3.

$\left[ \begin{array}{ccc|c} 1 & -1 & 1 & 20 \\ 0 & 1 & -1 & -11 \\ 0 & 5 & -2 & -31 \end{array} \right]$

• Eliminate the entry in the second column of the third row. Combine -5 (row 2) with row 3.

$\left[ \begin{array}{ccc|c} 1 & -1 & 1 & 20 \\ 0 & 1 & -1 & -11 \\ 0 & 0 & 3 & 24 \end{array} \right]$

• Multiply row 3 by 1/3.

$\left[ \begin{array}{ccc|c} 1 & -1 & 1 & 20 \\ 0 & 1 & -1 & -11 \\ 0 & 0 & 1 & 8 \end{array} \right]$

• Eliminate the entry in the third column of the second row. Combine row 2 with row 3.

$\left[ \begin{array}{ccc|c} 1 & -1 & 1 & 20 \\ 0 & 1 & 0 & -3 \\ 0 & 0 & 1 & 8 \end{array} \right]$

• Eliminate the entries in the second and third columns of the first row. Combine row 1 with row 2 and -1 (row 3).

$\left[ \begin{array}{ccc|c} 1 & 0 & 0 & 9 \\ 0 & 1 & 0 & -3 \\ 0 & 0 & 1 & 8 \end{array} \right]$

Then the solution to the system is

$\boxed{x=9, y=-3, z=8}$

If you want to use G elimination and substitution, you'd stop at the step with the augmented matrix

$\left[ \begin{array}{ccc|c} 1 & -1 & 1 & 20 \\ 0 & 1 & -1 & -11 \\ 0 & 0 & 1 & 8 \end{array} \right]$

The third row tells us that $z=8$ . Then in the second row,

$y-z = -11 \implies y=-11 + 8 = -3$

and in the first row,

$x-y+z=20 \implies x=20 + (-3) - 8 = 9$

5 0

2 years ago

What is the equation of a vertical line through the point (3, 2)?

dsp73

Answer:

If you consider what the slope looks like for a vertical line, it is an infinite slope. What that means is that you cannot have a y-value in your equation:

x = 3

This x-value would be a vertical line that passes through all y-values for x = 3. So you can replace them in (3, y) with any value, and it will be included in the linear equation x = 3.

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3 years ago

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How would I set up the equation to find mRQS on this circle?

Leni [432]

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3 years ago

Evaluate the expression

Natalka [10]

Answer: -5

Step-by-step explanation: