The solution to the equation is p = 1/3 and q = undefined
<h3>How to solve the equation?</h3>
The equation is given as:
p^2 - 2qp + 1/q = (p - 1/3)
The best way to solve the above equation is by the use of a graphing calculator i.e. graphically
However, it can be solved algebraically too (to some extent)
Recall that the equation is given as:
p^2 - 2qp + 1/q = (p - 1/3)
Split the equation
So, we have
p^2 - 2qp + 1/q = 0
p - 1/3 = 0
Solve for p in p - 1/3 = 0
p = 1/3
Substitute p = 1/3 in p^2 - 2qp + 1/q = 0
So, we have
(1/3)^2 - 2q(1/3) + 1/q = 0
This gives
1/9 - 2/3q + 1/q = 0
This gives
2/3q + 1/q = -1/9
Multiply though by q
So, we have
2/3q^2 + 1 = -1/9q
Multiply through by 9
6q^2 + 9 = -q
So, we have
6q^2 + q + 9 = 0
Using the graphing calculator, we have
q = undefined
Hence. the solution to the equation is p = 1/3 and q = undefined
Read more about equations at:
brainly.com/question/13763238
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Let h = the number of horses in the field
Let c = number of cows in the field
There are 2 more horses than cows in the field. Therefore
h = c + 2
or
c = h - 2 (1)
There are 15 animals in the field. Therefore
h + c = 15 (2)
Substitute (1) into (2).
h + (h - 2) = 15
2h - 2 = 15
Answer:
The correct equation is
2h - 2 = 15
Answer:
The balance after 1 year is;
$1,014.05
Step-by-step explanation:
To do this, we use the compound interest formula
That will be ;
A =P (1 + r/n)^nt
A is the amount generated which we want to calculate
r is the rate = 1.4% = 0.014
P is the amount deposited = $1,000
n is the number of times it is compounded annually which is 2 (semi-annually means 2 times in a year)
this the number of years which is 1
we have this as:
A = 1,000( 1 + 0.014/2)^(2*1)
A = 1,000(1 + 0.007)^2
A = 1,000(1.007)^2
A = $1,014.05
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√12*√18
2√3√18
2√3 x 3√2
2 x 3√3 x 2
2 x 3√6
6√6 or 14.696938
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