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lord [1]
2 years ago
10

Please hellp me mmmmmmmmeeeeeeeeeee

Mathematics
1 answer:
luda_lava [24]2 years ago
3 0
0.2 if 1 Mile is 5 Minutes then every 0.1 mile is 30 seconds so 1 minute would be 0.2
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An owner of a company spends $25 on office supplies. The owner is left with $20. Write an equation to find how much money he ori
aleksandr82 [10.1K]
$20+$25=$45 therefore the owner of the company originally had $45
4 0
2 years ago
Read 2 more answers
Which of the following represents the factorization of trinomal below
My name is Ann [436]
A is the correct answer.......

Here is the work shown:

x^2-x-20

A is the correct answer because when using the distributive property it is the only example that results in x^2-x-20.

(x+4)(x-5)

x*x=x^2, x*-5=-5x, 4*x=4x, 4*-5=-20. Now combine all alike terms for your final answer. x^2-x-20..

please vote my answer brainliest. thanks!
5 0
3 years ago
What is x^2=7x <br><br> number 9
ipn [44]

Let's do this in steps, show your work!

<u>#1. We need to move all terms to one side.</u>

<u>x^2 - 7x = 0</u>

<u>#2. Then factor out the common term x.</u>

<u>x(x - 7) = 0.</u>

<u>#3. Simplify to get..</u>

<u>x = 0, 7.</u>

<u />

If you need help with any other question let me know.

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8 0
2 years ago
Radioactive Decay Beginning with 16 grams of a radioactive element whose half -life is 30 years ,the mass y(in grams) remaining
Flura [38]

Answer:

the equation should be corrected to fit the data of the problem.  With the corrected equation a mass of 0.5 grams remains after 150 years

Step-by-step explanation:

for the mass y( in grams)

y=23* (1/2)^(t/45), t ≥ 0.

the initial mass is at t=0 , then

y= 23 grams  → should be 16 grams

half-life from the equation = 45 years → should be 30 years

the correct equation should be

y=16*(1/2)^(t/30), t ≥ 0

then after 150 years  → t= 150

y=16*(1/2)^(150/30)= 16*(1/2)^5 = 16/32 = 0.5 grams

then a mass of 0.5 grams remains after 150 years

5 0
2 years ago
Please I need this quick!!! 15 points
professor190 [17]
Let the number be n.

Then:

n^2 + (1/n)^2 = 82/9; find n.  Find the LCD; it is 9n^2.

Mult all 3 terms by 9n^2:
                                                                  82*9n^2
9n^4 + 9 = (82/9)(9n^2)  =>    9n^4 + 9 = ------------  
                                                                        9
Then 9n^4 - 82n^2 + 9 = 0

I used my graphing calculator to find that n = 3.  

Let's check:     is 3^2 + (1/3)^2 = 82/9?
                        Is   9   + 1/9 = 82/9?
                        Is  81 + 1 = 82?   YES.  So, n=3 is a solution.

7 0
2 years ago
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