To solve the question we shall use the formula for the range given by:
Horizontal range, R=[v²sin 2θ]/g
plugging in our values we get:
500=[160²×sin 2θ]/10
5000=160²×sin 2θ
0.1953=sin 2θ
thus:
arcsin 0.1953=2θ
11.263=2θ
hence:
θ=5.6315°~5.63
10:15 should be it ratios are easy.
Answer:
8, 16, 64
Step-by-step explanation:
8 = 2^3 . . . a perfect cube
16 = 4^2 . . . a perfect square
32 = 2^5 . . . neither a cube nor a square
64 = 2^6 = 4^3 = 8^2 . . . both a perfect cube and a perfect square
128 = 2^7 . . . neither a cube nor a square
