Answer:
0.12m/s
Explanation:
v=λf
Given that, λ = 12cm = 0.12m
T = 1second
(A period T is the time required for one complete cycle of vibration to pass a given point)
frequency 'f' is unknown but we can get frequency from f = 1/T = 1/1 = 1Hz
therefore, v= 0.12 × 1 = 0.12m/s
Solution:
54 / 9 = 6 boxes.
Answer
given,
length of rod (L)= 6 m
weight of the rod (W)= 10 N
rotates at = 240 rev/min
=
= 25.13 rad/s
a) Rotational inertia of the rod about axis of rotation
d is the distance from the center of gravity.
d = L/2
I = 27.55 kg.m²
rotational moment of inertia of the rod is equal to I = 27.55 kg.m²
b)angular momentum of rod
L = I ω
L =27.55 x 25.13
L = 692.36 Kg.m²/s
angular momentum of rod is equal to L = 692.36 Kg.m²/s
P=mv. So doubling the velocity doubles the momentum. (Doubling the mass alone would do the same thing. Doubling both would then quadruple it)