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3 years ago

If an object is accelerating, it is traveling the same distance for each time interval of its motion

Physics

2 answers:

Elenna [48]3 years ago

6 0

The answer is false :)

Anika [276]3 years ago

4 0

Answer:

false

Explanation:

if an object is accelerating the object will not travel the same distance every time interval

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Hello, I wanted an answer from a mathematician. The number 1.04 is closer to the number 1, 2, 1.25 or 1.5.

babymother [125]

Answer:

Explanation:

Of the 4 numbers given, the answer is 1 or A

If you take the absolute value of abs(1 - 1.04) you get 0.04.

(2 - 1.04) = 0.96

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1.5 - 1.04 = 0.46

The last three are all larger than 0.04

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2 years ago

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2 years ago

A kind of foliated metamorphic rock a. coal b. limestone c. marble d. slate

djyliett [7]

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3 years ago

Read 2 more answers

A compact disc rotates from rest up to an angular speed of 31.4 rad/s in a time of 0.892 s.

Serggg [28]

Answer:

(a) α = 35.20 rad/s^2

(b) θ = 802°

(d) a = 156.64 cm/s^2

Explanation:

(a) To find the angular acceleration of the disc you use the following formula:

$\alpha=\frac{\omega-\omega_o}{t}$ (1)

w: angular speed of the disc = 31.4 rad/s

wo: initial angular speed = 0 rad/s

t: time = 0.892s

You replace the values of the parameters in the equation (1):

$\alpha=\frac{31.4rad/s-0rad/s}{0.892s}=35.20\frac{rad}{s^2}$

The angular acceleration of the disc, for the given time, is 35.20rad/s^2

(b) To calculate the angle describe by the disc in such a time you use:

$\theta=\frac{1}{2}\alpha t^2$ (2)

$\theta=\frac{1}{2}(35.20rad/s^2)(0.892s)^2=14.00rad$

In degrees you have:

$\theta=14.00rad*\frac{180\°}{\pi \ rad}=802\°$

The angle described by the disc is 802°

(c) To calculate the tangential speed of the microbe for t=0.892s, you use the following formula:

$v=\omega r$ (3)

w: angular speed for t = 0.892s = 31.4rad/s

r: radius of the disc = 4.45cm

$v=(31.4rad/s)(4.45cm)=139.73\frac{cm}{s}$

The tangential speed is 139.73 cm/s

(d) The tangential acceleration is calculated by using the following formula:

$a=\alpha r$

α: angular acceleration for t=0.892s

$a=(35.20rad/s^2)(4.45cm)=156.64\frac{cm}{s^2}$

The tangential acceleration is 156.64cm/s^2

7 0

3 years ago

A charged particle with charge of 2 (uC) and mass 10-20 (kg) is traveling with velocity of 108 (m/s) in space. The charge reache

-BARSIC- [3]

Answer:

Explanation:

A ) Let the angle be θ between magnetic field and velocity of charged particle

Force created on charged particle F

= Bqv sinθ, B is magnetic field , q is charge , v is velocity of charged particle

F = .05 x 2 x 10⁻⁶ x 10⁸ x sinθ

8 = 10 sinθ

sinθ = .8

θ = 53°.

B )

acceleration = force / mass

= 8 / 10⁻²⁰

= 8 x 10²⁰ m / s²

3 0

3 years ago