All categories

3 years ago

If an object is accelerating, it is traveling the same distance for each time interval of its motion

Physics

2 answers:

Elenna [48]3 years ago

6 0

The answer is false :)

Anika [276]3 years ago

4 0

Answer:

false

Explanation:

if an object is accelerating the object will not travel the same distance every time interval

You might be interested in

Sound wave A has a lower frequency than sound wave B, but both waves

Keith_Richards [23]

Answer: C

Explanation: Amplitude controls loudness, and frequency controls pitch. The more frequent the higher pitch.

4 0

3 years ago

Read 2 more answers

The meaning of magnetism

never [62]

Magnetism is <span>a physical phenomenon produced by the motion of electric charge, resulting in attractive and repulsive forces between objects.</span>

5 0

3 years ago

Deep in the interiors of the giant planets, water is still a liquid even though the temperatures are tens of thousands of degree

Nataliya [291]

Answer:

High pressure inside the giant planet

Explanation:

As we move in the interior of the giant planet, the pressure and temperature in the interior of the planet increases. Since, the giant planets have hardly any solid surface and thus they are mostly constituted of atmosphere.

Also, the gravitational forces keep even the lightest of the matter bound in it contributing to the large mass of the planet.

If we look at the order of the magnitude of the temperature of these giant planets than nothing should be able to stay in liquid form but as the depth of the planet increases with the increase in temperature, pressure also increases which keeps the particle of the matter in compressed form.

Thus even at such high order of magnitude water is still found in liquid state in the interior of the planet.

7 0

3 years ago

Twenty is the _________________ of potassium

Mumz [18]

Twenty is the atomic number of potassium.

7 0

4 years ago

A ball of mass m is attached to a string of length L. It is being swung in a vertical circle with enough speed so that the strin

forsale [732]

Answer:

$\frac{m}{r}(v_b^2-v_t^2)+2mg$

Explanation:

When the ball is at the bottom position of the vertical circle, the forces acting on the ball are:

- The tension in the string, $T_b$ , upward

- The weight of the ball, $mg$ , downward

The resultant of these forces must be equal to the centripetal force, which points upward as well (towards the center of the circle), so:

$T_b-mg=m\frac{v_b^2}{r}$ (1)

where $v_b$ is the speed of the ball at the bottom of the circle, r the radius of the circle, and m the mass of the ball.

When the ball is at the top position of the vertical circle, the weight still acts downward, however the tension in the string also acts downward, so the equation of the forces becomes:

$T_t+mg=m\frac{v_t^2}{r}$ (2)

where

$T_t$ is the tension in the string in the top position

$v_t$ is the speed of the ball in the top position

By subtracting eq.(2) from eq.(1), we find:

$T_b-mg-(T_t+mg)=m\frac{v_b^2}{r}-m\frac{v_t^2}{r}\\T_b-T_t=\frac{m}{r}(v_b^2-v_t^2)+2mg$

So, this is the difference in tension between the two positions.

7 0

4 years ago

Read 2 more answers