Answer:
A) 1/3 D) 13/39 E) 14/42
Step-by-step explanation:
hope this helps. brainliest please.
Answer:
x=1+4/5 this is the answer i think
Step-by-step explanation:
Draw diagonal AC
The triangle ABC has sides 17 and 25
Say AB is 17, BC is 25
Draw altitude on side BC from A , say h
h = 17 sin B
Area = 25*17 sin B = 408
sin B = 24/25
In ∆ ABC
Cos B = +- 7/25
= 625 + 289 — b^2 / 2*25*17
b^2 = 914 — 14*17 = 676
b = 26
h = 17*24/25 = 408/25 = 16.32
Draw the second diagonal BD
In ∆ BCD, draw altitude from D, say DE =h
BD^2 = h^2 + {(25 + sqrt (289 -h^2) }^2
BD^2 = 16.32^2 + (25 + 4.76)^2
= 885.6576 + 266.3424
BD = √ 1152 = 33.94 m
Answer:
Step-by-step explanation:
https://d1avenlh0i1xmr.cloudfront.net/large/53ca8d0d-
BE is congruent to overline CF since they are altitudes of the same trapezoid(S).
AB is congruent to overline CD (Given)
AE is congruent to overline FD by the Hypotenuse Leg Theorem.
triangle ABC is congruent to triangle DCF (SSS Triangle Congruence)
angle A is congruent to angle D since corresponding parts of congruent triangles are congruent.
