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Zepler [3.9K]
3 years ago
7

The equation is (9+6)+4=(5+ blank)+4​

Mathematics
2 answers:
rusak2 [61]3 years ago
4 0
10 is your answer!! hope this helps
Luba_88 [7]3 years ago
3 0

Answer:

10

Step-by-step explanation:

(9 + 6) + 4 = (5 + x) + 4

15 + 4 = 5 + x + 4

19 = x + 9

19 - 9 = x

10 = x

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Find the angle, in degrees between 0 and 360∘, which intersects the unit circle at the point (−1/2,3/√2).
Vlada [557]

Answer:

it approx 103.2 degree

Step-by-step explanation:

s=90+tan^-1(1÷3√2)

I add 90 base on the coordinate , taking the centre of the circle place at origin

6 0
3 years ago
Find the missing side of the triangle<br> (7 and 14 btw)
jasenka [17]

Answer:

B. 7\sqrt{3}

Step-by-step explanation:

3 0
3 years ago
Multiple choice!! There's only one correct answer.
GalinKa [24]

The solution is where the red line crosses the blue line, which on the X axis is between the 1 and the 2, so about 1.5.

Convert the fractions to decimal and see which one is  close to 1.5:

13/8 = 1.625

25/16 = 1.5625

7/4 = 1.75

27/16 = 1.6875

The closest one to 1.5 is 25/16

5 0
3 years ago
| 2p -1 | =45, what are the values of p?
Alex73 [517]

Answer:

p = 23       and p = -22

Step-by-step explanation:

| 2p -1 | =45

Absolute value equations have 2 solutions, one positive value and one negative

2p-1 = 45    and 2p-1 = -45

Add 1 to all sides

2p-1+1 = 45+1    and 2p-1+1 = -45+1

2p = 46                        2p = -44

Divide by 2

2p/2 = 46/2    and   2p/2  = -44/2

p = 23       and p = -22

5 0
3 years ago
Read 2 more answers
Giving the 2 sides of the triangle, find the range of all possible lengths for the third side.
Zinaida [17]

Answer:

  1. 2 < x < 16
  2. 3 < x < 19
  3. 14 < x < 18
  4. 4 < x < 16
  5. 13 < x < 47
  6. 0 < x < 10
  7. 1 < x < 7

Step-by-step explanation:

The minimum third side is the difference of the given sides; the maximum third side is their sum.

If you like, you can have a spreadsheet calculate these for you. That seems like more work than just doing them in your head.

4 0
3 years ago
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