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kramer
3 years ago
12

Bobby had 36 books in his locker. Some were library books, some were textbooks, and the rest were telephone books. The number of

library books and telephone books combined equals twice the number of textbooks. The number of textbooks and telephone books combined equals three times the number of library books. How many of each type of book were in Bobby's locker?
Mathematics
1 answer:
emmainna [20.7K]3 years ago
8 0
Make variables for each
L = library books
P = telephone books
T = text books

so.... L+P = 2T 
now we have to fill in numbers
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3 years ago
James age is 3 years less than twice Tori's age the sum of their ages is 30 find their ages
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3 years ago
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rusak2 [61]

Answer:

1). 183

2). 83

3). 353

4). -2652

5). 59

6). 510

7). -293

8). 79

9). 78

10). 87

Step-by-step explanation:

Considering order of operation, parenthesis must be simplified first.

The solutions to the given questions are shown below;

1). \ \ 5+(7\times (3+2)^2) + 3=8 +  (7\times (5)^2)  = 8 + (7\times 25) = 8 + 175 = 183

2). \ 16+(8+ (6+2)^2) - 5=16-5 +  (8+ (8)^2)  = 11 + (8+64) = 11 + 72 = 83

3). \ (15+ 3)^2 + ((14+6)+3^2)= (18)^2 + ((20) + 9) = 324 + (29) = 353

4). \ ((11+ 2)-(24+2)^2)\times 2^2 = (13 - 676) \times 4  = (-663)\times 4 = -2652

5). \ ((4+3)^2+ 6) -5+3^2= (49 + 6) - 5 + 9= (49+6+9) - 5 = 64-5 = 59

6). \ (20+ 2)^2 +((15+7)+2^2)= (484) + (22+ 4)= 484 + 26 =510

7). \ ((12 + 4)- (15+3)^2+ 5^2 = (16 -  324) + 25 = -318 + 25 = -293

8). \ (6^2+ (24+ 3+5^2)) - 3^2= (36 + (52)) - 9 = (88) - 9 = 79

9). \ ((10-4)^2\times 2) + 2 + 2^2= ((6)^2 \times 2) + 2 + 4 = (36\times 2)+ 6 = 72 + 6 = 78

10). \ (7^2 + (16 + 8 + 2^2)) + 3^2 = (49 + 28) + 9 = 78 + 9 = 87

3 0
3 years ago
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3 years ago
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