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finlep [7]
3 years ago
15

Given the set : {5, 8, 8, 10, 10, 11, 15, 17, 20), what is the probability of a choosing a number at random from the list and th

at number being 8?​
Mathematics
1 answer:
In-s [12.5K]3 years ago
8 0

Answer:

i think it would be a 24% chance

Step-by-step explanation:

i think

You might be interested in
R2-44r+120= -30 + 11r <br> Solve by factoring
Sunny_sXe [5.5K]

Answer:

r = 152/55

Step-by-step explanation:

122 - 44r = - 30 + 11r

122 - 44r - 11r = - 30

- 44r - 11r = - 30 - 122

- 55r = - 30 - 122

- 55r = - 152

4 0
3 years ago
The need the rate of change please
garik1379 [7]

Answer:

m=\frac{-3}{2}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Slope Formula: m=\frac{y_2-y_1}{x_2-x_1}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Find points from graph.</em>

Point (0, 0)

Point (2, -3)

<u>Step 2: Find slope </u><em><u>m</u></em>

Simply plug in the 2 coordinates into the slope formula to find slope <em>m</em>. Rate of change is the same as slope.

  1. Substitute [SF]:                    m=\frac{-3-0}{2-0}
  2. Subtract:                              m=\frac{-3}{2}
5 0
3 years ago
What's the GCF of 30,48,60
scoray [572]
The greatest common factor (GCF) of 30, 48, and 60 is: 6

Factors for 30: 1, 2, 3, 5, 6, 10, 15, 30
Factors of 48: 1, 2, 3, 4, 6, 8, 12, 16, 24
Factors of 60: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30

The common factors between them are 1, 2, 3, and 6, but 6 is the greatest.
6 0
3 years ago
In a sample of 234 individuals over the age of 25, chosen at random from the state of Oregon, 48 did not have a high school dipl
Anna71 [15]

Answer:

The upper bound of a 95% confidence interval for the proportion of individuals over the age of 25 in Oregon who do not have a high school diploma is of 0.2568.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

95% confidence level

So \alpha = 0.05, z is the value of Z that has a p-value of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

In a sample of 234 individuals over the age of 25, chosen at random from the state of Oregon, 48 did not have a high school diploma.

This means that n = 234, \pi = \frac{48}{234} = 0.2051

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2051 + 1.96\sqrt{\frac{0.2051*0.7949}{234}} = 0.2568

The upper bound of a 95% confidence interval for the proportion of individuals over the age of 25 in Oregon who do not have a high school diploma is of 0.2568.

6 0
3 years ago
P - 3 1/6 = -2 1/2<br> what is p?
goldfiish [28.3K]
<span>P - 3 1/6 = -2 1/2

3 1/6- 21/2 

p=2/3 </span>
7 0
3 years ago
Read 2 more answers
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