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saw5 [17]
3 years ago
6

Plzzzz help meeeeeeeeeeeeeeeeeeeeeeeeeeee

Mathematics
1 answer:
Nezavi [6.7K]3 years ago
7 0

Answer:

12×-20) mm

Step-by-step explanation:

because you times 12 and 20

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Direction: Arrange the following numbers in decreasing order. Write your answer on the blank provided below each number.
rjkz [21]

Answer:

1. 100 000, 89 000, 67 000, 55 000

2. 45 678, 34 567, 23 456, 12 345

3. 98 765, 87 654, 76 543, 65 432-

7 0
3 years ago
A bus is traveling at 50 mph. If the rate of speed increases 3 mph each hour, how long will it be before the bus is traveling at
arsen [322]

Answer:

It will take 10 hours.

Step-by-step explanation:

By using the formula of motion,

v = u + at

Here, v = Final speed of an object

u = initial speed

a = Acceleration by which the speed is increasing

t = Duration or time

Now substitute the values given in the question,

80 = 50 + 3t

3t = 30

t = 10 hours

Therefore, after 10 hours speed of the bus will be 80 mph.  

4 0
3 years ago
Write the function in vertex form, and identify its vertex. g(x) = 5x2 - 50x + 128
steposvetlana [31]
Hello : 
<span>g(x) = 5x² - 50x + 128    
       = 5(x²-10x +128/5)
       = 5 (x²-10x+5²-5² +128/5)
        = 5 ((x-5)² +128/5 -125/5)
y = 5 ((x-5)² - 3/5)
y= 5(x-5)² +3.....vertex form
the vertex is : (5,3)</span>
3 0
3 years ago
Enter the coefficients of the fifth Taylor polynomial T5(x) for the function f(x) = x5−3x4+2x2+5x−2 based at b=1. T5(x)= + (x−1)
DENIUS [597]

Compute the necessary values/derivatives of f(x) at x=1:

f(1)=3

f'(1)=2

f''(1)=-12

f'''(1)=-12

f^{(4)}(1)=48

f^{(5)}(1)=120

Taylor's theorem then says we can "approximate" (in quotes because the Taylor polynomial for a polynomial is another, exact polynomial) f(x) at x=1 by

T_5(x)=\dfrac3{0!}+\dfrac2{1!}(x-1)-\dfrac{12}{2!}(x-1)^2-\dfrac{12}{3!}(x-1)^3+\dfrac{48}{4!}(x-1)^4+\dfrac{120}{5!}(x-1)^5

T_5(x)=3+2(x-1)-6(x-1)^2-2(x-1)^3+2(x-1)^4+(x-1)^5

###

Another way of doing this would be to solve for the coefficients a,b,c,d,e,g in

f(x)=a+b(x-1)+c(x-1)^2+d(x-1)^3+e(x-1)^4+g(x-1)^5

by expanding the right hand side and matching up terms with the same power of x.

5 0
3 years ago
Solve for d<br> –3d + 10 − 5d = –10 − 10d
deff fn [24]
Your answer would be -2
6 0
2 years ago
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