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3 years ago

Write the equation of the line through (-2,1) and parallel to y= -3x+1

1 answer:

7 0

Use point slope equation y-y1=m(x-x1) Remember that a parallel line has the same slope.

y-1= -3(x-(-2))
y-1= -3(x+2)
y-1= -3x-6
y= -3x-5

Final answer: y=-3x-5

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slamgirl [31]

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3 years ago

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) The density of oil in a circular oil slick on the surface of the ocean at a distance of r meters from the center of the slick

Feliz [49]

Answer:

Therefore the mass of the of the oil is 409.59 kg.

Step-by-step explanation:

Let us consider a circular disk. The inner radius of the disk be r and the outer diameter of the disk be (r+Δr).

The area of the disk

=The area of the outer circle - The area of the inner circle

= $\pi (r+\triangle r)^2- \pi r^2$

$=\pi [r^2+2r\triangle r+(\triangle r)^2-r^2]$

$=\pi [2r\triangle r+(\triangle r)^2]$

Since (Δr)² is very small, So it is ignorable.

∴ $A=2\pi r\triangle r$

The density $\delta (r)= \frac{40}{1+r^2}$

We know,

Mass= Area× density

$=(2r \pi \triangle r)(\frac{40}{1+r^2}})$

Total mass $M=\sum_{i=1}^n \frac{80r_i\pi }{1+r^2}\triangle r_i$

Therefore

$\sum_{i=1}^n \frac{80r_i\pi }{1+r^2}\triangle r_i=\int_0^5 \frac{80r\pi }{1+r^2}dr$

$=40\pi[ln(1+r^2)]_0^5$

$=40\pi [ln(1+5^2)-ln(1+0^2)]$

$=40\pi ln(26)$

= 409.59 kg (approx)

Therefore the mass of the of the oil is 409.59 kg.

3 0

2 years ago

Tom's statement shows a previous balance of $2452.64 a payment of $160 a new transactions totaling $138 what is his new balance

Gemiola [76]

His new balance will be $805.8915

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It would be B: a set of points that extends infinitely in two directions

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2 years ago

3/10 in.=7/8 mi. (i am doing rates and ratios)

harkovskaia [24]

3/10 in
1 in =(1/12)ft 
1 ft =(1/5280) mi 

3/10 in=3/10*(1/12)*(1/5280) mi

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3 years ago