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3 years ago

8

Zuri had $125 saved in a bank account each month ziti spends $10 let x represent the number of months and f(x) represent the acc

ount balance
PLS ANSWER NOW

1 answer:

Shtirlitz [24]3 years ago

8 0

Answer:

I'm pretty sure it would be f(x) = 125x - 10

Step-by-step explanation:

You might be interested in

Ponderosa Paint and Glass carries three brands of paint. A customer wants to buy another gallon of paint to match paint she purc

sveta [45]

Answer:

$\frac{4}{9}$

Step-by-step explanation:

Two events are independent of each other, this is called Compound Probability. Classical example is if two coins are filped, what is the probability of getting two heads in a row.?

Answer: each has 50% probability because there are two states only, either H or T. since we have two coins the probability of getting two heads in row is the product of obtaining heads for each individual coin (which is independent of each other). or is $\frac{1}{2}$ × $\frac{1}{2}$ = $\frac{1}{4}$ = 25%. (Notice!).

Back to our problem, now here we have 3 paint brands and one of them is the right paint brand and two of them are not correct brands. so the prabablity that the customer has picked not correct brand is $\frac{2}{3}$ and her husband has not picked correct brand is also $\frac{2}{3}$ , since two probabilities are compound probabilities i.e indepandant of each other the probablity that both woman and her husband fail get correct brand is the product of the two and is = $\frac{2}{3}$ × $\frac{2}{3}$ = $\frac{4}{9}$ .

4 0

2 years ago

What is the quotient when 4x3 + 2x + 7 is divided by x + 3?

Arte-miy333 [17]

Answer:

The quotient of this division is $(4x^2 -12x + 38)$ . The remainder here would be $-26$ .

Step-by-step explanation:

The numerator $4x^3 + 2x + 7$ is a polynomial about $x$ with degree $3$ .

The divisor $x + 3$ is a polynomial, also about $x$ , but with degree $1$ .

By the division algorithm, the quotient should be of degree $3 - 1 = 2$ , while the remainder shall be of degree $1 - 1 = 0$ (i.e., the remainder would be a constant.) Let the quotient be $a\,x^2 + b\, x + c$ with coefficients $a$ , $b$ , and $c$ .

$4x^3 + 2x + 7 = \left(a\,x^2 + b\, x + c\right)(x + 3)$ .

Start by finding the first coefficient of the quotient.

The degree-three term on the left-hand side is $4 x^3$ . On the right-hand side, that would be $a\, x^3$ . Hence $a = 4$ .

Now, given that $a = 4$ , rewrite the right-hand side:

$\begin{aligned}&\left(4\,x^2 + b\, x + c\right)(x + 3) \cr =& \left(4x^2 + (b\, x + c)\right)(x + 3) \cr =& 4x^2(x + 3) + (bx + c)(x + 3) \cr =& 4x^3 + 12x^2 + (bx + c)(x + 3)\end{aligned}$ .

Hence:

$4x^3 + 2x + 7 = 4x^3 + 12x^2 + (b\,x + c)(x + 3)$

Subtract $\left(4x^3 + 12x^2\right$ from both sides of the equation:

$-12x^2 + 2x + 7 = (b\,x + c)(x + 3)$ .

The term with a degree of two on the left-hand side has coefficient $(-12)$ . Since the only term on the right hand side with degree two would have coefficient $b$ , $b = -12$ .

Again, rewrite the right-hand side:

$\begin{aligned}&\left(-12 x + c\right)(x + 3) \cr =& \left(-12 x+ c\right)(x + 3) \cr =& (-12x)(x + 3) + c(x + 3) \cr =& -12x^2 -36x + (bx + c)(x + 3)\end{aligned}$ .

Subtract $-12x^2 -36x$ from both sides of the equation:

$38x + 7 = c(x + 3)$ .

By the same logic, $c = 38$ .

Hence the quotient would be $(4x^2 - 12x + 38)$ .

6 0

3 years ago

Which of the following expressions is a sixth root of unity?

sukhopar [10]

-1 for apex i just answered this question and got it right

8 0

3 years ago

Read 2 more answers

Can anyone solve this asap? i’m completing a final.

Allisa [31]

Answer:

Step-by-step explanation:

The right option es a)

because the general form is:

ax^2+bx+c

so you can easyly identify b=-5

7 0

2 years ago

3.<br> If r=9.b=5, and g=-6, what does (r +b-8)(b + g) equal?

VLD [36.1K]

Answer:

-6

Step-by-step explanation:

r = 9, b = 5, g = -6

Plug these values into (r + b - 8)(b + g)

[(9) + (5) - 8]*[(5) + (-6)]

Combine like terms in the brackets

[6]*[-1]

6 times -1 equals -6, so that is your answer

8 0

2 years ago