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3 years ago

Find the x and y intercept. 3x + 2y = 12

Mathematics

2 answers:

Mumz [18]3 years ago

6 0

Answer:x(-4,0) y(0,6)

Step-by-step explanation:

3×- 2.0 = -12

X=4

3(0)-2y= -12

X= 6

iris [78.8K]3 years ago

4 0

Answer:

x=4 y=6

Step-by-step explanation:

12 divide by 3 = 4

12 divide by 2 = 6

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Answer:

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Step-by-step explanation:

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3 years ago

Nine times the sum of a number and 26 is at most -25

kobusy [5.1K]

Answer:

x ≤ -259/9

Step-by-step explanation:

Change into a number equation 9(x + 26) ≤ -25

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3 years ago

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jekas [21]

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3 years ago

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Anettt [7]

Answer:

136

Step-by-step explanation:

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3 0

3 years ago

Read 2 more answers

A fair coin is flipped twelve times. What is the probability of the coin landing tails up exactly nine times?

seraphim [82]

Answer:

$P\left(E\right)=\frac{55}{1024}$

Step-by-step explanation:

Given that a fair coin is flipped twelve times.

It means the number of possible sequences of heads and tails would be:

2¹² = 4096

We can determine the number of ways that such a sequence could contain exactly 9 tails is the number of ways of choosing 9 out of 12, using the formula

$nCr=\frac{n!}{r!\left(n-r\right)!}$

Plug in n = 12 and r = 9

$=\frac{12!}{9!\left(12-9\right)!}$

$=\frac{12!}{9!\cdot \:3!}$

$=\frac{12\cdot \:11\cdot \:10}{3!}$ ∵ $\frac{12!}{9!}=12\cdot \:11\cdot \:10$

$=\frac{1320}{6}$ ∵ $3!\:=\:3\times 2\times 1=6$

$=220$

Thus, the probability will be:

$P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}$

$=\frac{220}{4096}$

$=\frac{55}{1024}$

Thus, the probability of the coin landing tails up exactly nine times will be:

$P\left(E\right)=\frac{55}{1024}$

4 0

3 years ago