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anastassius [24]
3 years ago
8

Q7 Find the missing angle x

Mathematics
1 answer:
Kryger [21]3 years ago
7 0

Answer:

Step-by-step explanation:

Thales theorem tells us that B is a 90

and therefore from W to o (center) is 45°

we know the total of the arc VoW is 98

180= 8x +1  + 45 +98

36 = 8x

4.5 = x

x = 4.5

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Please help ill mark brainliest
sp2606 [1]

Answer: She is correct because the average of the numbers 2, 3, 1, 4, 5, 2, 3, 4, 3, is 3.

Step-by-step explanation:

To find average you add all of the listed numbers, (2, 3, 1, 4, 5, 2, 3, 4, 3) which is 27. You then divide 27 by the amount of listed numbers, which is 9. 27 divided by 9 is 3. There for the average amount of strokes it takes to hit the ball into the hole of each green is 3.

Hope this helps! Please rate, it helps me know if I am explaining the answers well enough or not!! Thank you!<3

7 0
3 years ago
(5xy^2-x^2y)+3x^2y <br> Equals what?
Savatey [412]

(5xy^2-x^2y)+3x^2y=5xy^2+(-x^2y+3x^2y)\\\\=5xy^2+2x^2y

6 0
4 years ago
-
REY [17]

The true statement about the graph of the function f(x) = x3 - 2x2 + 4x – 8 is (B) The function has 1 real zero that occurs 1 time.

<h3>How to determine the true statement</h3>

The function of f(x) is represented as:

f(x)=x^3-2x^2+4x-8

Differentiate the function f(x)

f'(x)=3x^2-4x+4

Calculate the minimum value using:

x = -\frac b{2a}

So, we have:

x = -\frac {-4}{2*3}

x = \frac {2}{3}

Substitute 2/3 in f'(x)

f'(2/3)=3*(2/3)^2-4(2/3)+4

f'(2/3)=\frac 83

The value of f'(2/3) is greater than 0.

This means that the function f(x) has 1 real zero, and it occurs once at point (2,0)

Hence, the true statement is (b)

Read more about functions at:

brainly.com/question/13136492

3 0
3 years ago
Please show work.<br> 3. Solve the given inequality and graph the solution on a number line.
adelina 88 [10]

Answer:where’s the number line?

Step-by-step explanation:

8 0
3 years ago
The width of a soccer field must be between 55yd and 80 yd. a. What compound inequality represents the width of a soccer field?
puteri [66]
Jdkskkdodosoeoepehdjsisjsjsdjd
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