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anastassius [24]
3 years ago
8

Q7 Find the missing angle x

Mathematics
1 answer:
Kryger [21]3 years ago
7 0

Answer:

Step-by-step explanation:

Thales theorem tells us that B is a 90

and therefore from W to o (center) is 45°

we know the total of the arc VoW is 98

180= 8x +1  + 45 +98

36 = 8x

4.5 = x

x = 4.5

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The Big Ben clock tower in London stands at a height of 316 feet. What is the metric equivalent in meters?
RideAnS [48]
96.31680m is the answer
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What’s the slope? explain please
kykrilka [37]
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On the slope a transverse line between 4, (-4)

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3 years ago
If a number is chosen at random from the set {1, 2, 3, 4, . . ., 18}, what is the probability that the number chosen is a factor
choli [55]
Looking at the set, we are given 18 elements. 17 is prime; it has only two factors: 1 and 17, since 1•17=17. So, the question is really asking what is the probability the numbers 1 or 17 is chosen. As mentioned earlier, 17 is prime, so there are two possible choices: 1 and 17.

P (probability) = possible outcomes / total outcomes

It is important to note that these events are “or” events, meaning that the probability can only be determined by choosing a 1 or a 17; you can’t randomly chose a 1 and 17 at the same time. So, the formula is:

P(A or B) = P(A) + P(B)

All this is saying is that given two possible outcomes, the probability occurs independent of each event; they don’t occur at the same time.

P(1 or 17) = P(1)/18 + P(1)/18

P(1 or 17) = 2/18

Since 17 is prime, it’s two and only factors are 1 and 17. The probability of randomly choosing a 1 or 17 is 2/18, meaning that there are 2 elements in the set out of a possible 18 elements that can be randomly chosen.

2/18 simplifies to 1/9


So, your answer is 1/9
5 0
2 years ago
Can some one please help me <br><br>solve: 6(x+4) = 30
DochEvi [55]

Answer:

6(x+4)=30

6x+24=30

6x+24-24=30-24

x=6/6

x=1

Step-by-step explanation:

Hope this helps you

Mark me as brainliest

4 0
3 years ago
Read 2 more answers
Solve the radical equation. Check all purpose solutions. <br><br> Sqrt(4-3x) = x
alisha [4.7K]

Step-by-step explanation:

√(4-3x) = x

1. square both sides:

[√(4-3x)]²= (x) ²

4-3x = x²

2. shift all the terms to the right side

(minimise dealing with negative coefficient of x² terms to prevent careless mistakes)

0= x²+3x-4

no matter how you change the places of the terms, it will still be:

x²+3x-4=0

3. solve the quadratic equation, either by cross multiplication(and factorising) or the quadratic formula(if you're taught)

for me I will be using the cross multiplication table that my calculator can help me with(gives me the solution but better to show the factorised form to prevent missing out method marks)

as such:

x²+3x-4=0

(x+4)(x-1)=0

hence:

(x+4)=0 or (x-1)=0

finally:

x= -4 or x= 1

however we're not done yet as some solutions may not match with the question/ original equation provided, this we still need to check if there are any values that does not match

substitute x= -4 into the original equation:

√4-3(-4) = √4+12 = √16 = 4 > -1 , hence x= -1 is not the answer

you can substitute the values into a scientific calculator(that has the functions required) to quickly determine

then to double confirm, do the same for the other value of X that we have found:

√4-3(1) = √4-3 = √1 = 1

since the other value of x matches with the equation provided in the question, then we can now confirm that the value of x=1 is the correct value

reason for such situation to happen:

remember in step 1 when we squared both sides of the equation, that is the reason for having to check for the correct X value. let me explain further

when we square numbers, we are potentially introducing another possible answer other than the correct answer intended for us to find as well as to match with the question.

for example:

1 = 1² = (-1)²

likewise, I can even take any other number to compare, such as 100:

100=10²=(-10)²

and this scenario only happens for the even powers of x, such as x², x⁴, x⁶ so on and so forth.

hence whenever such questions come out, do remember to double check with the original question/equation

lastly, the checking portion will only apply for even powers of x in questions and/or when you happen to square them

hope this helps!

5 0
1 year ago
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