Answer:
4 a 1
Step-by-step explanation:
Se lee "4 a 1"
Answer:
Step-by-step explanation:
Researchers measured the data speeds for a particular smartphone carrier at 50 airports.
The highest speed measured was 76.6 Mbps.
n= 50
X[bar]= 17.95
S= 23.39
a. What is the difference between the carrier's highest data speed and the mean of all 50 data speeds?
If the highest speed is 76.6 and the sample mean is 17.95, the difference is 76.6-17.95= 58.65 Mbps
b. How many standard deviations is that [the difference found in part (a)]?
To know how many standard deviations is the max value apart from the sample mean, you have to divide the difference between those two values by the standard deviation
Dif/S= 58.65/23.39= 2.507 ≅ 2.51 Standard deviations
c. Convert the carrier's highest data speed to a z score.
The value is X= 76.6
Using the formula Z= (X - μ)/ δ= (76.6 - 17.95)/ 23.39= 2.51
d. If we consider data speeds that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant?
The Z value corresponding to the highest data speed is 2.51, considerin that is greater than 2 you can assume that it is significant.
I hope it helps!
Notice that the reflection is over a line of the form x=constant; in this case, the y-coordinate of the reflected point stays the same while the x-coordinate changes as expressed by the transformation below
Hence, in our case
Transform points N, M, and O accordingly,
<h2>Therefore, the answer is the first option (top to bottom)</h2>
Answer:
(c-a, 0)
Step-by-step explanation:
The horizontal space between (c, b) and P is the same as the space between (a, b) and O.
Coordinates are written (x, y), where x is for horizontal space.
P is on the x-axis, making the y-coordinate 0.
(a+c, 0) would be to the right of the entire parallelogram.
(c, 0) would be directly below (c, b).
(a-c, 0) would be to the left of the entire parallelogram and in the other quadrant.
Answer:
- 2 < x < 2
Step-by-step explanation:
Given
- 3 < 2x + 1 < 5 ( subtract 1 from each interval )
- 4 < 2x < 4 ( divide each interval by 2 )
- 2 < x < 2
