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marissa [1.9K]
3 years ago
9

How many moles of iron is needed to react completely with 5.00 moles of sulfur to form iron

Chemistry
1 answer:
Ghella [55]3 years ago
3 0

Answer:

5 moles of Fe(II) are required to react completely with the 5 moles of Sulphur

Explanation:

The balanced equation in this question is

Iron + Sulfur = Iron(II) Sulfide

Fe (II) + S --> Fe(II)S

Thus one mole of sulfur reacts with one mole of Fe(II)

Hence, 5 moles of Fe(II) are required to react completely with the 5 moles of Sulphur

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FCH₂CH₂F will form Intermolecular Hydrogen bond

FCH₂CH₂F has H-F atoms linked together by Hydrogen bond whereas in HOCH₂CH₂OH here, carbon is linked with oxygen and oxygen is again linked with Hydrogen.

<h3>What is Intermolecular Hydrogen bond ?</h3>

Intermolecular hydrogen bonding refers to the formation of hydrogen bonds between molecules of the same or distinct substances. As an illustration, consider hydrogen bonds in water, alcohol, ammonia, etc.

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I think the answer as communicating findings.

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If you lift an object that weighs 13 pounds through a distance of 3 feet, you have done foot-pounds of work.
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Name 5 affects of weathering and erosion
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If I have 4.5 liters of gas at a temperature of 33 0C and a pressure of 6.54 atm, what will be the pressure of the gas if I rais
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This is an exercise in the general or combined gas law.

To start solving this exercise, we must obtain the following data:

<h3>Data:</h3>
  • V₁ = 4.5 l
  • T₁ = 33 °C + 273 = 306 k
  • P₁ = 6.54 atm
  • T₂ = 94 °C + 273 = 367 k
  • V₂ = 2.3 l
  • P₂ = ¿?

We use the following formula:

  • P₁V₁T₂ = P₂V₂T₁ ⇒ General Formula

Where

  • P₁ = Initial pressure
  • V₁ = Initial volume
  • T₂ = Initial temperature
  • P₂ = Final pressure
  • V₂ = Final volume
  • T₁ = Initial temperature

We clear the general formula for the final pressure.

\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{P_{1}V_{1}T_{2} }{V_{2}T_{1}}  \ \to \ Clear \ formula \end{gathered}$}

We solve by substituting our data in the formula:

\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{(6.54 \ atm)(4.5 \not{l})(367 \not{K}) }{(2.3 \not{l})(306 \not{k})}  \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{10800.81}{ 703.8 } \ atm  \end{gathered}$}

\boxed{\large\displaystyle\text{$\begin{gathered}\sf P_{2}=15.346 \ atm \end{gathered}$} }

If I raise the temperature to 94°C and decrease the volume to 2.3 liters, the pressure of the gas will be 15,346 atm.

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2 years ago
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