First let's define vertex: A point on the curve with a local minimum or maximum of curvature. If we look for the minimum and maximum value of the equation y=x^2+5: minimum value X=0, substitute in the equation to get the maximum value of Y y = 0^2 + 5y = 0 + 5y= 5 so the ordered pair is (0,5) Hope That Helped =D
Answer:
800 nuts
Step-by-step explanation:
i hope this helps
A quadratic equation may be expressed in vertex form as:
y = a(x - h)² + k, the vertex being (-h , k)
For option A, the vertices are visibly different. (-4 , 0) and (4 , 0)
For B, the graphs' vertices are the same, (0 , 0).
For C, the vertices (can be obtained by differentiating and putting equal to 0) are (0 , -4) and (0 , 4)
For D, the vertices are (4 , 0) and (0 , 4)
Thus, the answer is B.
Whaaaaa——t i dont understand too
2 because it is the only number smaller than 5
