(1,3) and (7,3) falls on the same horizontal line. hence, the distance is just equal to 6 units. (7,3) and (7,7) meanwhile lie on the same vertical line. hence the distance is 4. (7,7) and (4,7) lie on the same horizontal line with a distance of 3.
Finally, to get back to point (1,3) - (4,7) ----> (1,3), 3 to the left and 4 down, the diagonal being 5.
6+4+3+5= 10 + 8 = 18.
Answer:
97/113
Step-by-step explanation:
67 robots have legs only, 21 have wheels only, and 9 have both legs and wheels. The total number of robots with legs and/or wheels is 97.
The probability is 97/113.
#2, Y=8, x=3
because if you subsitute those variables in,
8=3+5
4x3+8=20
Algebraically that would be expressed as 2r + 11
The product of 2 and r is 2r.
The sum of 2r and 11 is 2r + 11
