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3 years ago

please help me with this i asked last time but it didn’t some the important stuff so i’m just putting a picture ^

Mathematics

1 answer:

Licemer1 [7]3 years ago

3 0

I think its B but i cant help much cuz i got a quiz thats due soon

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To use the HL Theorem to prove two triangles are congruent, the triangles must be right triangles. Which other conditions must a

mr Goodwill [35]

To use HL specifically they would need to have the same hypotenuse as well as a right angle.

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3 years ago

Read 2 more answers

The number of new cars purchased in a city can be modeled by the equation C=20t to the 2nd power, where C is the number of new c

Allisa [31]

Answer:

$1998 + 5\sqrt{30}$

Step-by-step explanation:

Set up the equation:

Since C(t) gives the number of cars purchased in the t-th year after 1998, then make the number of cars equal to 15 000 and solve for t - the year:

20t^2 = 15000

t^2 = 750

t = $\sqrt{750} = \sqrt{10} \cdot \sqrt{25} \cdot \sqrt{3} = 5\sqrt{30}$

The year will be simply 1998 + 5 \sqrt{30}

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3 years ago

Which line is perpendicular to y= -3/4x+ 2 if the line passes through the point (3,5)?

iren2701 [21]

Answer:jjdvdudbufh f

Step-by-step explanation:

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3 years ago

Jacob Lee is a frequent traveler between Los Angeles and San Diego. For the past month, he wrote down the flight times in minute

valkas [14]

Solution :

We know that

$H_0: \mu_1 = \mu_2=\mu_3$

$H_1 :$ At least one mean is different form the others (claim)

We need to find the critical values.

We know k = 3 , N = 35, α = 0.05

d.f.N = k - 1

= 3 - 1 = 2

d.f.D = N - k

= 35 - 3 = 32

SO the critical value is 3.295

The mean and the variance of each sample :

Goust Jet red Cloudtran

$\overline X_1 =50.5$ $\overline X_2 =50.07143$ $\overline X_3 =55.71429$

$s_1^2=19.96154$ $s_2^2=14.68681$ $s_3^2=36.57143$

The grand mean or the overall mean is(GM) :

$\overline X_{GM}=\frac{\sum \overline X}{N}$

$=\frac{51+51+...+49+49}{35}$

= 52.1714

The variance between the groups

$s_B^2=\frac{\sum n_i\left( \overline X_i - \overline X_{GM}\right)^2}{k-1}$

$=\frac{\left[14(50.5-52.1714)^2+14(52.07143-52.1714)^2+7(55.71426-52.1714)^2\right]}{3-1}$

$=\frac{127.1143}{2}$

= 63.55714

The Variance within the groups

$s_W^2=\frac{\sum(n_i-1)s_i^2}{\sum(n_i-1)}$

$=\frac{(14-1)19.96154+(14-1)14.68681+(7-1)36.57143}{(14-1)+(14-1)+(7-1)}$

$=\frac{669.8571}{32}$

= 20.93304

The F-test statistics value is :

$F=\frac{s_B^2}{s_W^2}$

$=\frac{63.55714}{20.93304}$

= 3.036212

Now since the 3.036 < 3.295, we do not reject the null hypothesis.

So there is no sufficient evidence to support the claim that there is a difference among the means.

The ANOVA table is :

Source Sum of squares d.f Mean square F

Between 127.1143 2 63.55714 3.036212

Within 669.8571 32 20.93304

Total 796.9714 34

3 0

2 years ago

The length of a side of an equilateral triangle is 40cm. what is the length of the altitude of the triangle?

podryga [215]

Answer:

20√3 cm

Step-by-step explanation:

Altitude of an equilateral triangle splits it into 2 equal right triangles, it bisects the base and the angle opposite to the base.

<u>Let the altitude be x. Then as per Pythagorean theorem:</u>

x² = 40² - (40/2)²
x²= 1600 -400
x²= 1200
x= √1200
x= 20√3 cm

<u>Correct choice is</u> the second one

4 0

3 years ago