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dimaraw [331]
3 years ago
14

What is (8+7 + 3.3) times ( 1/2) ^2

Mathematics
1 answer:
nadya68 [22]3 years ago
3 0

Answer & Step-by-step explanation: 4.58

<em>PEMDAS:</em>

<em>Parenthesis first! (8 + 7 + 3.3) = 18.3</em>

<em>Exponents second! </em>1/2^{2}<em> = 1/4 = 0.25</em>

<em>Multiply third and solve! 18.3 x 0.25 = 4.575</em>

<em>Round if needed! </em><em>4.575</em><em> = </em><em>4.58</em><em> = </em><em>4.6</em><em> = </em><em>5</em>

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Answer:

where's the equation? your question is missing some parts.

Step-by-step explanation:

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3 years ago
Can someone please help me with this?
lidiya [134]
The angle formed by two tangles results in half of the difference of the two arcs. 

That is to say 

70 = .5(Major arc - minor arc)

Think of the major arc as the larger and the minor the smaller.

So therefore the difference in the two arcs = 140 (multiplying both sides of the above equation by 2.

140 = major arc - minor arc.

Another necessary idea is that the arc of a whole circle = 360 degrees, that is to say the major arc + minor arc = 360, giving us a second equation to solve.
Assuming x is the minor arc.

140 = major arc - x 
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3 years ago
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(8, -5)

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7 0
3 years ago
A peony plant with red petals was crossed with another plant having streaky petals. A geneticist states that 75% of the offsprin
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Answer:

The sample data confirm the geneticist's prediction that 75% of the offspring from this cross will have red flowers.

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A Chi-square goodness of fit test can be used to test the claim made by the geneticist.

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<em>Hₐ</em>: There is a significant difference between the observed and expected value, i.e. <em>p</em>₁ > 0.75.

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\chi^{2}=\sum \frac{(O-E)^{2}}{E}

Consider the tables attached below.

The value of the test statistic is:

\chi^{2}=\sum \frac{(O-E)^{2}}{E}=25.8133

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*Use a Chi-square table.

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The null hypothesis is rejected at 1% level of significance.

<u>Conclusion</u>:

As the null hypothesis is rejected it can be concluded that 75% of the offspring from this cross will have red flowers.

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