-5 is the answer I believe
ρ - density, m - mass, V - volume
Liquid A:
Liquid B:
Liquid C:
The density of liquid C is approximately 0.96 g/cm³.
The value of the 3 in 395,047 is 10 times greater than the
value of the 3 in 136,258.
What is the place value of a number?
In mathematics, place value refers to a digit's location within a number. A number has a slot for each digit. The placement of each digit will be enlarged when we represent the number in general form. These positions begin at the unit place, often known as the individual's position. Units, tens, hundreds, thousands, ten thousand, one hundred thousand, and so on are the place values of a number's digits from right to left.
Given, the number in consideration is 395,047.
The place value of 3 in the given number is hundred thousands.
A value 10 times smaller than this given number must have three in the ten thousands place.
Out of 386592, 283429, 136258, 123694; only 136258 has three in ten thousands place.
Therefore, the value of the 3 in 395,047 is 10 times greater than the
value of the 3 in 136,258.
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The greatest common facter of 12 and 38 is 2 so the answer is:
2 ft
Answer:
v = 8.49 m/s rounded off to 3 significant figures
Step-by-step explanation
Using Energy Conservation
U = Tk + Vp (Sum of kinetic Tk Energy and gravitational potential Vp Energy)
- At height = 3.67 m, the hammer was still or the velocity was negligible; hence, vi = 0 m/s.
- Ui = 0 + mgh
- At ground all potential energy is converted to kinetic; hence, Uf =
mv². - Since total energy of the system remains constant we equate Ui to Uf.
- Ui = Uf
- mgh = mv²
- After cancelling out masses and making v the subject of the formula we get:
v = ![\sqrt[2]{2gh}](https://tex.z-dn.net/?f=%5Csqrt%5B2%5D%7B2gh%7D)
= ![\sqrt[2]{2*9.81*3.67}](https://tex.z-dn.net/?f=%5Csqrt%5B2%5D%7B2%2A9.81%2A3.67%7D)
= 8.49 m/s rounded off to 3 significant figures
