Nine groups of 8 students and one group of 6 students. 9 x 8 = 72. 78 - 72 = 6.
Try making a grid like this. Apologies for the terrible drawing and handwriting. It represents all possible results of rolling two dice and summing their values. The blue column and yellow row represent the values of each die, and the green numbers reptesent their sums.
First, you can see that there are 36 possible values. Second, it's easy to see how many results are greater than 9, since they're all in one corner. And last, you can see just how many are even and how many are odd. Remember to reduce your fractions in the end.
Answer:
The intersection points are (-1,0) and (10,0)
Step-by-step explanation:
Brainliest if i am right? uwu
Answer:
Length = 9units
Width = 7units
Step-by-step explanation:
It is said that the length is 2units more than the width
Assume that the width is x, then the length will be 2 + x
ie
Width = x
Length = 2 + x
Area of the rectangle = 63units
Area of rectangle = l * b
l - length of the rectangle
b - width of the rectangle
A = l * b
63 = (2 + x) * x
63 = ( 2 + x) x
63 = 2x + x^2
Let's rearrange it
x^2 + 2x - 63 = 0
Let's find the factor of 63
A factor that can be multiplied to give -63 and that can be added to give +2
Let's use -7 and +9
x^2 - 7x + 9x - 63 = 0
Separate with brackets
( x^2 - 7x) + ( 9x - 63) = 0
x( x - 7) + 9(x - 7) = 0
( x + 9)(x - 7) = 0
( x + 9) = 0
( x - 7) = 0
x + 9 = 0
x = -9
x - 7 = 0
x = 7
Note: the length of a rectangle can not be negative
So therefore,
x = 7
Length = 2 + x
= 2 + 7
= 9units
Width = x
= 7units