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Pepsi [2]
3 years ago
13

Prove that the angles at the base of an isosceles triangle are acute

Mathematics
1 answer:
garik1379 [7]3 years ago
7 0
1. Since it is an isosceles triangle, we know that the two length sides have to be the same. Therefore, the angles across from the sides are the same. They cannot be 90 degrees or above because 90+90+0 would mean we would have all the interior angles at 180 but the thing is the third angle cannot be zero. Therefore, the other two angles cannot be 90 or more. They must be acute.



Also, if it had two right angles (90 degrees) or more, it could not close to be a triangle.


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78 students are separated into groups of 8 for a field trip how many groups are there there are many students from a smaller gro
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Nine groups of 8 students and one group of 6 students. 9 x 8 = 72. 78 - 72 = 6.
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3 years ago
What is X^2 -8x+9=0 written in the form(x-P)^2 =q?
Olenka [21]
x^{2} -8x+9=0
x^{2} -8x=-9
x^{2} -8x+16=-9+16
(x-4)^{2}=7


8 0
4 years ago
Can someone help please and thank you
denis-greek [22]
Try making a grid like this. Apologies for the terrible drawing and handwriting. It represents all possible results of rolling two dice and summing their values. The blue column and yellow row represent the values of each die, and the green numbers reptesent their sums.
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8 0
4 years ago
What are the intersection points of the function: (x - 9)(x + 1) = (x + 1) *
nlexa [21]

Answer:

The intersection points are (-1,0) and (10,0)

Step-by-step explanation:

Brainliest if i am right? uwu

4 0
3 years ago
The length of a rectangle is 2 units more than the width. The area of the rectangle is 63 units. What is the length, in units, o
Keith_Richards [23]

Answer:

Length = 9units

Width = 7units

Step-by-step explanation:

It is said that the length is 2units more than the width

Assume that the width is x, then the length will be 2 + x

ie

Width = x

Length = 2 + x

Area of the rectangle = 63units

Area of rectangle = l * b

l - length of the rectangle

b - width of the rectangle

A = l * b

63 = (2 + x) * x

63 = ( 2 + x) x

63 = 2x + x^2

Let's rearrange it

x^2 + 2x - 63 = 0

Let's find the factor of 63

A factor that can be multiplied to give -63 and that can be added to give +2

Let's use -7 and +9

x^2 - 7x + 9x - 63 = 0

Separate with brackets

( x^2 - 7x) + ( 9x - 63) = 0

x( x - 7) + 9(x - 7) = 0

( x + 9)(x - 7) = 0

( x + 9) = 0

( x - 7) = 0

x + 9 = 0

x = -9

x - 7 = 0

x = 7

Note: the length of a rectangle can not be negative

So therefore,

x = 7

Length = 2 + x

= 2 + 7

= 9units

Width = x

= 7units

7 0
3 years ago
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