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Daniel [21]
3 years ago
5

Choose the statement that best describes the error in finding the volume of the solid.

Mathematics
1 answer:
stellarik [79]3 years ago
6 0

Answer:

the formula used gives surface area instead of volume

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How to do the problem
marta [7]
There are 153 people who each ate 1/4 pounds. Therefore, the amount of watermelon eaten is 153/4 pounds.
The amount of watermelon served is
8 \frac{1}{4}  + 9 \frac{1}{4}  + 8 \frac{7}{8}  + 9 \frac{5}{8}  + 10 \frac{3}{4}
=  \frac{8 \times 4 + 1}{4}  +  \frac{9 \times 4 + 1}{4}  \\  +  \frac{8 \times 8 + 7}{8}  +  \frac{9 \times 8 + 5}{8} \\  +  \frac{10 \times 4 + 3}{4}
=  \frac{33}{4}  +  \frac{37}{4}  +  \frac{71}{8}  +  \frac{77}{8}  +  \frac{43}{4}  \\  =  \frac{33 \times 2}{4 \times 2}  +  \frac{37 \times 2}{4 \times 2}  +  \frac{71}{8}  \\  +  \frac{77}{8}  +  \frac{43 \times 2}{4 \times 2}
=  \frac{66 + 74 + 71 + 77 + 86}{8}
=  \frac{374}{8}  =  \frac{186}{4}
There is 186/4 total watermelon. Minus the 153/4 that was eaten,
\frac{186 - 153}{4}  =  \frac{33}{4}  = 8 \frac{1}{4}

The leftover watermelon is 8 & 1/4 pounds.
6 0
2 years ago
Help help ASAP!!!!!!!!
Georgia [21]

Answer:

d = 25.12

Step-by-step explanation:

volume = 144 pie cm cubed

h = 9

d = (144 pie cm cubed / 9) / 2

d = 25.12

6 0
2 years ago
Area of sector................................
sveticcg [70]

Answer:

A ≈ 25.1 cm²

Step-by-step explanation:

the area (A) of the sector is calculated as

A = area of circle × fraction of circle

  = πr² × \frac{\frac{4\pi }{9} }{2\pi }

  = π × 6² × \frac{\frac{4\pi }{9} }{2\pi }

  = 36π × \frac{\frac{4\pi }{9} }{2\pi }

  = 18 × \frac{4\pi }{9}

  = 2 × 4π

  = 8π

  ≈ 25.1 cm² ( to the nearest tenth )

3 0
2 years ago
5 plus 2 times 10 equals
Goryan [66]
The answer is 70.
 5 + 2 = 7 
 7 x 10 = 70
6 0
3 years ago
Read 2 more answers
HELP ME PLEASE IVE BEEN STRUGGLING WITH THIS FOR SO LONG
Ber [7]

Answer:

<h2>m∠ACE = 90°</h2>

Step-by-step explanation:

Figure Interpretation:

m∠CBA + m∠CDE = 180

m∠BCA = (180-m∠CBA)/2

m∠DCE = (180-m∠CDE)/2

=======================

Then

m∠BCA + m∠DCE = (180-m∠CBA)/2 + (180-m∠CDE)/2

                                = [360-(m∠CBA+m∠CDE)]/2

                                = [360 - 180]/2

                                = 90

finally,

m∠ACE= 180 - (m∠BCA + m∠DCE)

             = 180 - 90

             = 90

8 0
2 years ago
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