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levacccp [35]
3 years ago
14

Choose the equation below that represents the line passing through the point (1, −4) with a slope of one half.

Mathematics
1 answer:
AVprozaik [17]3 years ago
6 0

Answer:

the equation would be y=1/2x-9/2

Step-by-step explanation:

next time try to put the answers like the question did because that's always helpful

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What percentage of 48 is 62?
Mila [183]

Answer:

129

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Two coworkers commute from the same building. They are interested in whether or not there is any variation in the time it takes
jenyasd209 [6]

Answer:

Step-by-step explanation:

Hello!

You have two samples.

Sample 1 (time that takes one commute of worker 1)

n₁= 20

S₁²= 12.2

Sample 2 (time that takes one commute of worker 2)

n₂= 20

S₂²= 16.9

The hypothesis is that the first coworker is more consistent with his commute times, this means that the variability of his commute times is less than the variability of the commute times of worker 2. With this in mind, the hypothesis for a variance ratio test is:

H₀: σ₁² ≥ σ₂²

H₁:: σ₁² < σ₂²

α: 0.10

The statistic for this test is:

F= (S₁²/S₂²) * (σ₁²/σ₂²) ~ F_{n1-1;n2-1}

The test is one-tailed (left) with just one critical value:

F_{n_1-1;n_2-1;\alpha } = \frac{1}{F_{n_2-1;n_1-1;1-\alpha }} = \frac{1}{F_{19;19;0.90}} = \frac{1}{1.82} =0.549

(The F-table I use only has the values for high probabilities so I've used a conversion method to obtain the value for the small probability)

Your decision rule is:

If F ≤ 0.549, you reject the null hypothesis.

if F > 0.549, you support the null hypothesis.

The calculated value:

F= (S₁²/S₂²) * (σ₁²/σ₂²) = (12.2/16.9) * 1= 0.722

Since the calculated F-value is greater than the critical value, the decision is to not reject the null hypothesis. So you can say that the variability of the commute times of worker 1 is less than the variability of the commute times of worker 2.

I hope you have a SUPER day!

7 0
3 years ago
Which table represents viable solutions for y = 5x, where x is the number of tickets sold for the school play and y is the amoun
oksian1 [2.3K]

Answer:

I think the second table.

Step-by-step explanation:

Because it is the correct one.

5 0
3 years ago
The equation 13x + 1 = 5 – x can be solved by graphing y = 13x + 1 and y = 5 – x.
shusha [124]

Answer:

The graph shows that when x =3 both

\frac{1}{3}x + 1

and 5 – x equal 2

Step-by-step explanation:

The equation 13x + 1 = 5 – x can be solved by graphing y = 13x + 1 and y = 5 – x.

From the graph, the two lines representing the two equations intersect at (3,2).

This implies that the solution to the system

y =  \frac{1}{3} x + 1

and

y=5-x

is x=3, y=2

Hence the value of the two functions equals 2 at x=3.

7 0
3 years ago
Rowena can paint a room in $14$ hours, while Ruby can paint it in $6$ hours. If Rowena paints for $x$ hours and Ruby paints for
LUCKY_DIMON [66]

Question

Rowena can paint a room in 14 hours, while Ruby can paint it in 6 hours. If Rowena paints for x hours and Ruby paints for y hours, they will finish half of the painting, while if Rowena paints for y hours and Ruby paints for x hours they will paint the whole room. Find the ordered pair (x,y)

Answer:

(x, y) = (231/40, 21/40)

where x = 231/40

y = 21/40

Step-by-step explanation:

From the question, we are told:

Rowena can paint a room in = 14 hours

Ruby can paint it in = 6 hours.

This means

In one hour.

Rowena can paint = 1/14 of the room

Ruby can paint =1/6 hour of the room

From the question, we are told that :

If Rowena paints for x hours and Ruby paints for y hours, they will finish half of the painting

This is represented mathematically as:

(1/14)(x) + ( 1/6)(y) = 1/2...... Equation 1

Also we were told that:

if Rowena paints for y hours and Ruby paints for x hours they will paint the whole room

(1/14)(y) + (1/6)(x) = 1 .......... Equation 2

Bringing the two equations together, we have:

(1/14)(x) + ( 1/6)(y) = 1/2 ....... Equation 1

(1/14)(y) + (1/6)(x) = 1 ............ Equation 2

We find the Lowest common multiple of the numerator 14 and 6 = 42. Hence, we multiply both equations through by 42

3x + 7y = 21 ....... Equation 3

7x + 3y = 42 ......... Equation 4

To solve for x and y in Equation 3 and 4 we would be using the Elimination method

21x + 49y = 147 .......... Equation 5

21x +9y = 126 ........... Equation 6

21x + 49y = 147 .......... Equation 5

-(21x +9y = 126) ........... Equation 6

40y = 21

y = 21/40

To get the value of x , we would substitute 21/40 for y in Equation 3

3x + 7y = 21 ....... Equation 3

3x + 7(21/40) = 21

3x + 147/40 = 21

3x = 21 - 147/40

3x = 693/40

x = (693/40) ÷ 3

x = 693/40 × 1/3

x = 693/120

x = 231/40

Therefore, (x, y) = (231/40, 21/40)

3 0
3 years ago
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