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marin [14]
3 years ago
5

Here’s the question to my last post :) anyways

Mathematics
1 answer:
hichkok12 [17]3 years ago
5 0

1 Pint 4 Fluid Ounces!

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Find the lateral area of this pyramid whose base is a regular hexagon with a side length of 3cm and whose slant height is 12cm.
juin [17]

Answer:

108 cm^2

Step-by-step explanation:

The lateral surface area of a pyramid is given as

LSA= 1/2×perimeter of the base×slant height

base is hexagon with side 3 cm , therefore, perimeter of the base

=6×3=18 cm

slant height = 12 cm

thus, LSA = 1/2×18×12 = 108 cm^2

4 0
3 years ago
Helppp pleaseee
Oliga [24]
B.28 Years Hope it help
7 0
3 years ago
I need help with this ASAP please!!
Ilia_Sergeevich [38]

Answer:

Translation 1 unit left

Step-by-step explanation:

we have

f(x)=x

g(x)=(x+1)

we know that

The rule of the transformation of f(x) to g(x) is equal to

f(x) ------> g(x)

(x,y) -----> (x-1,y)

That means----> The translation is 1 unit to the left

6 0
3 years ago
The quantity r varies jointly with t and u and inversely with s when t= -12, u= -7, and s= -4, r= -126. Find r when t= -8, u= 8,
vichka [17]

Answer:

r = 64

Step-by-step explanation:

r = (k*t*u)/s

Where,

k = constant of proportionality

t = -12,

u= -7,

s= -4,

r= -126.

r = (k*t*u)/s

-126 = (k*-12*-7)/-4

-126 * -4 = 84k

504 = 84k

k = 504/84

k = 6

Find r when t= -8, u= 8, and s= -6.

r = (k*t*u)/s

= (6*-8*8) / -6

= -384 / -6

= 64

r = 64

6 0
3 years ago
Need some math help please!
stellarik [79]

Hello!

In our triangle, c is the hypotenuse. We are given an adjacent side length to our angle. This means we will use the cosine. Let's find it first.

cos54≈0.59

This gives us the equation below.

0.59=9/c

0.59c=9

c≈15.25

Therefore, c is equal to about 15.25

I hope this helps!

8 0
3 years ago
Read 2 more answers
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