Here’s the question to my last post :) anyways
1 answer:
You might be interested in
sinФ = 1/6
sinФ = opposite/hypotenuse
cosФ = adjacent/hypotenuse
tanФ = opposite/adjacent
SOHCAHTOA
1^(2)+b^(2)=6^(2)
1+b^(2)=36
b^(2)=35
cosФ = /6
tanФ = 1/ =
/35