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3 years ago

7

At Wendy’s, 3 Baconators and 2 Frosty’s cost $21.50. If 5 Baconator’s and 1 Frosty cost $30, find the cost of one Baconator and

one Frosty.

1 answer:

Verizon [17]3 years ago

5 0

Suggartits it’s easy the answer is 3Baconatore 2 frosty free points bby

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Suppose that the quantity supplied S and quantity demanded D of T-shirts at a concert are given by the following functions wher

harkovskaia [24]

Answer:

Step-by-step explanation:

The demand function is expressed as

D(p )=1150-50p

The supply function is expressed as S(p)=−200 + 40p

Where

p represents the price

A) The equilibrium price is the price at which the quantity supplied and the quantity demanded would be equal. Therefore

1150 - 50p = - 200 + 40p

40p + 50p = 1150 + 200

90p = 1350

p = 1350/90

p = 15

The equilibrium price is $15

b) For quantity demanded to be greater than quantity supplied, the price would be

1150 - 50p > - 200 + 40p

40p + 50p > 1150 + 200

90p > 1350

p > 1350/90

p > 15

The price would be greater than 15

c) if the quantity demanded is greater than the quantity supplied, the prices of the T shirt would increase.

7 0

3 years ago

What is the following product? <br>(4x square root 5x^2 + 2^2 square root 6)^2

tangare [24]

The product is $104 x^{4}+16 \sqrt{30} x^{4}$

Explanation:

The given expression is $\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}$

We need to determine the product of the given expression.

First, we shall simplify the given expression.

Thus, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x \sqrt{5} x+2 x^{2} \sqrt{6}\right)^2$

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)^2$

Expanding the expression, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)$

Now, we shall apply FOIL, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}\right)^{2}+2 ( 2 x^{2} \sqrt{6})(4 x^{2} \sqrt{5})+\left(2 x^{2} \sqrt{6}\right)^{2}$

Simplifying the terms, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=16 \cdot 5 x^{4}+16 \sqrt{30} x^{4}+4 \cdot 6 x^{4}$

Multiplying, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=80 x^{4}+16 \sqrt{30} x^{4}+24 x^{4}$

Adding the like terms, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=104 x^{4}+16 \sqrt{30} x^{4}$

Thus, the product of the given expression is $104 x^{4}+16 \sqrt{30} x^{4}$

7 0

3 years ago

If a person earns $275 per week, how much is earned in 26 weeks

WARRIOR [948]

Answer:

$7150

Step-by-step explanation:

To find how much is earned, take the amount earned per week times the number of weeks

275*26 =7150

4 0

3 years ago

What is y=x+1<br> y+2x=10

Sunny_sXe [5.5K]

Answer:

listin or read but i will try to help you as much as i can

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Pls, help!<br> Will give brainly for the correct answer <br> Due tonight!

zhannawk [14.2K]

7) 2

8) -3

9) -5/11

10) 2/5

11) -0.5

12) -2

7 0

3 years ago