How do you find a quadratic equation from a graph?
1 answer:
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Answer:
The equation of ellipse centered at the origin
Step-by-step explanation:
given the foci of ellipse (±√8,0) and c0-vertices are (0,±√10)
The foci are (-C,0) and (C ,0)
Given data (±√8,0)
the focus has x-coordinates so the focus is lie on x- axis.
The major axis also lie on x-axis
The minor axis lies on y-axis so c0-vertices are (0,±√10)
given focus C = ae = √8
Given co-vertices ( minor axis) (0,±b) = (0,±√10)
b= √10
The relation between the focus and semi major axes and semi minor axes are
The equation of ellipse formula
we know that
<u>Final answer:</u>-
<u>The equation of ellipse centered at the origin</u>
<u /><u />
<span>3x + y = 9 (I)
</span><span>y = –4x + 10 (II)
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</span>
Pass the incognito "4x" to the first term, changing the signal when changing sides.
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simplify by (-1)
</span>
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</span>
<span>
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</span>
<span>
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</span>
<span><span>
</span></span><span>Substitute in equation (I) to find the value of "Y".
</span>3x + y = 9 (I)
3*(1) + y = 9
3 + y = 9
y = 9 - 3
Answer:
</span><span>y = –4x + 10 (II)
------------------------
</span>
Pass the incognito "4x" to the first term, changing the signal when changing sides.
<span>-------------------------
simplify by (-1)
</span>
-------------------------
</span>
<span>
-------------------------
</span>
-----------
</span>
</span></span><span>Substitute in equation (I) to find the value of "Y".
</span>3x + y = 9 (I)
3*(1) + y = 9
3 + y = 9
y = 9 - 3
Answer: