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photoshop1234 [79]

2 years ago

9

Tom has some toy cars. 25 of them are red. He has 35 more green cars than red cars. The remaining 15 toy cars are yellow. Tom de

cides to pack 5 toy cars of the same colour in a box. How many more boxes of red and green toy cars are there than boxes of yellow toy cars?

1 answer:

horrorfan [7]2 years ago

8 0

Answer:

Step-by-step explanation:

red = 25

green = 25 + 35 = 60

yellow = 15

red = 25/5 = 5

green = 60/5 = 12

yellow = 15/5 = 3

Red + green = 5 + 12 = 17 boxes

yellow = 3 boxes

17 - 3 = 14 boxes

There are 14 more boxes of red and green cars than yellow cars.

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3 years ago

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Aliun [14]

Answer:

46

Step-by-step explanation:

Let $(ab)$ represent a number with $a$ in the ten's position and $b$ is the one's position.

This means $(ab)$ actually has value of $10a+b$ .

We are given the sum of those digits of $(ab)$ is 10; this means $a+b=10$ .

It says if 18 is added to the number $(ab)$ , then the result is $(ba)$ .

So $(ab)$ has value $10a+b$ and

$(ba)$ has value $10b+a$ .

We are given then:

$(ab)+18=(ba)$

$10a+b+18=10b+a$

Subtract $10a$ on both sides:

$b+18=10b+a-10a$

Simplify:

$b+18=10b-9a$

Subtract $b$ on both sides:

$18=10b-b-9a$

$18=9b-9a$

Divide both sides by 9:

$2=b-a$

Rearrange by commutative property:

$2=-a+b$

So the system of equations we want to solve is:

$a+b=10$

$-a+b=2$

-------------------------Add equations together (this will eliminate the variable $a$ and allow you to go ahead and solve for $b$ :

$0+2b=12$

$2b=12$

Divide both sides by 2:

$b=\frac{12}{2}$

Simplify:

$b=6$

If $b=6$ and $a+b=10$ , then $a=4$ . $a=4$ since 4+6=10.

So the original number is (46).

18 more than 46 is 18+46=(64) which is what we wanted.

We also have the sum of 4 and 6 is 10 as well.

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