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3 years ago

11

If an object is rotated clockwise 130° around a center and then counterclockwise 75° around the same center, what is the angle b

etween the original image and second image?

1 answer:

Keith_Richards [23]3 years ago

6 0

That would be 130 - 75 = 55 degrees answer

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Nookie1986 [14]

Answer:

$\frac{7}{8} \div \frac{1}{2} = \frac{7}{4}$

Step-by-step explanation:

Here we are given four equations and we have to find the equation that gives the number of half inches that are in $\frac{7}{8}$ inches.

To find how many half inches i.e. $\frac{1}{2}$ inches are there in $\frac{7}{8}$ inches we have to divide $\frac{7}{8}$ by $\frac{1}{2}$ .

So, the equation that will give the result is $\frac{7}{8} \div \frac{1}{2} = \frac{7}{8} \times \frac{2}{1} = \frac{7}{4}$ (Answer)

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2 years ago

The measure of c is .

mina [271]

Answer:

c^2=a^2+b^2

c^2=6^2+8^2

c^2=36+64

c=10

but still do not understand why peoples are asking that basic

4 0

2 years ago

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If 20+20 is 40 percent what is 20 of half percent.

hichkok12 [17]

I don’t know if this is correct: 40%

3 0

2 years ago

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a photographer is taking the 4th grade class picture. She stands on a ladder to get a better angle . From the top step of the la

Kruka [31]

Given:
a ladder with three steps.
top step is 45° angle.

45° / 3 steps = 15°

So, top step is 45°. Middle step is 30°. Bottom step is 15°. Ground is 0°

The photographer would shout on the bottom step at an angle of 15°.

4 0

3 years ago

With a detailed explanation from the internet<br> 1/(x-5)+3/(x+2)=4

irga5000 [103]

Answer:

$\boxed{ \sf x=\dfrac{4\pm\sqrt{43}}{2}}$

Explanation:

$\rightarrow \sf \dfrac{1}{x-5}+\dfrac{3}{x+2}=4$

<u>make the denominators same</u>

$\rightarrow \sf \dfrac{1(x+2)}{(x-5)(x+2)}+\dfrac{3(x-5)}{(x+2)(x-5)}=4$

<u>join the fractions together</u>

$\rightarrow \sf \dfrac{x+2+3x-15}{(x-5)(x+2)}=4$

<u>cross multiply</u>

$\rightarrow \sf x+2+3x-15=4(x-5)(x+2)$

<u>simplify</u>

$\rightarrow \sf 4x-13=4x^2-12x-40$

<u>group the variables</u>

$\rightarrow \sf 4x^2-16x-27 = 0$

<u>use quadratic formula</u>

$\rightarrow \sf x = \dfrac{-\left(-16\right)\pm \sqrt{\left(-16\right)^2-4\cdot \:4\left(-27\right)}}{2\cdot \:4}$

<u>simplify the following</u>

$\rightarrow \sf x=\dfrac{4\pm\sqrt{43}}{2}$

7 0

2 years ago

Read 2 more answers