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bekas [8.4K]
3 years ago
11

If an object is rotated clockwise 130° around a center and then counterclockwise 75° around the same center, what is the angle b

etween the original image and second image?
Mathematics
1 answer:
Keith_Richards [23]3 years ago
6 0
That would be 130 - 75  = 55 degrees answer
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Nookie1986 [14]

Answer:

\frac{7}{8} \div \frac{1}{2} = \frac{7}{4}

Step-by-step explanation:

Here we are given four equations and we have to find the equation that gives the number of half inches that are in \frac{7}{8} inches.

To find how many half inches i.e. \frac{1}{2} inches are there in \frac{7}{8} inches we have to divide \frac{7}{8} by \frac{1}{2}.

So, the equation that will give the result is \frac{7}{8} \div \frac{1}{2} = \frac{7}{8} \times \frac{2}{1} = \frac{7}{4} (Answer)

6 0
2 years ago
The measure of c is .
mina [271]

Answer:

c^2=a^2+b^2

c^2=6^2+8^2

c^2=36+64

c=10

but still do not understand why peoples are asking that basic

4 0
2 years ago
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If 20+20 is 40 percent what is 20 of half percent.
hichkok12 [17]
I don’t know if this is correct: 40%
3 0
2 years ago
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a photographer is taking the 4th grade class picture. She stands on a ladder to get a better angle . From the top step of the la
Kruka [31]
Given:
a ladder with three steps.
top step is 45° angle.

45° / 3 steps = 15°

So, top step is 45°. Middle step is 30°. Bottom step is 15°. Ground is 0°

The photographer would shout on the bottom step at an angle of 15°.
4 0
3 years ago
With a detailed explanation from the internet<br> 1/(x-5)+3/(x+2)=4
irga5000 [103]

Answer:

\boxed{ \sf x=\dfrac{4\pm\sqrt{43}}{2}}

Explanation:

\rightarrow \sf \dfrac{1}{x-5}+\dfrac{3}{x+2}=4

<u>make the denominators same</u>

\rightarrow \sf \dfrac{1(x+2)}{(x-5)(x+2)}+\dfrac{3(x-5)}{(x+2)(x-5)}=4

<u>join the fractions together</u>

\rightarrow \sf \dfrac{x+2+3x-15}{(x-5)(x+2)}=4

<u>cross multiply</u>

\rightarrow \sf x+2+3x-15=4(x-5)(x+2)

<u>simplify</u>

\rightarrow \sf 4x-13=4x^2-12x-40

<u>group the variables</u>

\rightarrow \sf 4x^2-16x-27 = 0

<u>use quadratic formula</u>

\rightarrow \sf x = \dfrac{-\left(-16\right)\pm \sqrt{\left(-16\right)^2-4\cdot \:4\left(-27\right)}}{2\cdot \:4}

<u>simplify the following</u>

\rightarrow \sf x=\dfrac{4\pm\sqrt{43}}{2}

7 0
2 years ago
Read 2 more answers
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