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Oksanka [162]
3 years ago
8

Determine the least common multiple of 16,28, and 56​

Mathematics
2 answers:
Inessa05 [86]3 years ago
8 0

Answer:

112

Step-by-step explanation:

Honestly I read the question wrong, but yea listen to the person above. I just woke up lol

Scrat [10]3 years ago
4 0

Answer:

112

Step-by-step explanation:

lauren(mod) PLEASE DONT DELETE MY ANSWERS WHEN THEY ARE CORRECT!!!!!

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Find the remaining trigonometric ratios of θ if csc(θ) = -6 and cos(θ) is positive
VikaD [51]
Now, the cosecant of θ is -6, or namely -6/1.

however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.

we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now

\bf csc(\theta)=-6\implies csc(\theta)=\cfrac{\stackrel{hypotenuse}{6}}{\stackrel{opposite}{-1}}\impliedby \textit{let's find the \underline{adjacent side}}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\pm\sqrt{6^2-(-1)^2}=a\implies \pm\sqrt{35}=a\implies \stackrel{IV~quadrant}{+\sqrt{35}=a}

recall that 

\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad\qquad 
cos(\theta)=\cfrac{adjacent}{hypotenuse}
\\\\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{adjacent}{opposite}
\\\\\\
% cosecant
csc(\theta)=\cfrac{hypotenuse}{opposite}
\qquad \qquad 
% secant
sec(\theta)=\cfrac{hypotenuse}{adjacent}

therefore, let's just plug that on the remaining ones,

\bf sin(\theta)=\cfrac{-1}{6}
\qquad\qquad 
cos(\theta)=\cfrac{\sqrt{35}}{6}
\\\\\\
% tangent
tan(\theta)=\cfrac{-1}{\sqrt{35}}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{\sqrt{35}}{1}
\\\\\\
sec(\theta)=\cfrac{6}{\sqrt{35}}

now, let's rationalize the denominator on tangent and secant,

\bf tan(\theta)=\cfrac{-1}{\sqrt{35}}\implies \cfrac{-1}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{-\sqrt{35}}{(\sqrt{35})^2}\implies -\cfrac{\sqrt{35}}{35}
\\\\\\
sec(\theta)=\cfrac{6}{\sqrt{35}}\implies \cfrac{6}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{6\sqrt{35}}{(\sqrt{35})^2}\implies \cfrac{6\sqrt{35}}{35}
3 0
3 years ago
What is the area of the shaded region?
Mekhanik [1.2K]

9514 1404 393

Answer:

  434 -49π ≈ 280.1 cm²

Step-by-step explanation:

The shaded area is the difference between the enclosing rectangle area and the circle area.

The rectangle is 14 cm high and 31 cm wide, so has an area of ...

  A = WH

  A = (31 cm)(14 cm) = 434 cm²

The circle area is given by ...

  A = πr²

  A = π(7 cm)² = 49π cm²

__

The shaded area is the difference of these, so is ...

  shaded area = rectangle - circle

  = (434 - 49π) cm² ≈ 280.1 cm²

4 0
2 years ago
2-5=x/1.2<br>(please solve this)​
Leni [432]

Step-by-step explanation:

x=3.6

semoga bermanfaat

meet belajar skuy

6 0
3 years ago
WHAT IS THE SLOPE OF THE LINE SHOWN BELOW
quester [9]
Slope is rise over run. So you "rise" 6 spaces from -1 to 5 and then you "run" 5 spaces to the right i believe it will be 6/5. 
4 0
3 years ago
Read 2 more answers
Write the equation of a line that passes through the point (-6, 8) and has a slope of 3.
MakcuM [25]

Answer:

Step-by-step explanation:

y - 8 = 3(x + 6)

y - 8 = 3x + 18

y = 3x + 10

answer is a

5 0
3 years ago
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