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Paraphin [41]
3 years ago
11

Unit 8: right triangles and trigonometry Homework 2: special right triangles HELP PLEASE!!

Mathematics
1 answer:
jeka943 years ago
7 0

Answer:

x=50

y=25

Step-by-step explanation:

So for this triangle we can use trig. To find side x (the hypotenuse) we can do sin60 degrees. *remember SOHCAHTOA, so sin is opposite over hypotenuse.

sin60degrees=(25 * sqrt of 3)/x

multiply each side by x to get xsin60degrees=25*sqrt of 3. Then divide both sides by sin60degrees. Plug that in a calculator and you should get 50.

For side y, well you can use the characteristics of 30-60-90 triangles and by doing this we know that the short leg of this type of triangle is HALF of the hypotenuse and half of 50 is 25. If you didn't know this you could still use the cos of 60 degrees and get 25 as well.

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What is the equation for the points (-3,1) and (9,7)
Scorpion4ik [409]

Answer:

The equation of line with given points is 2Y - X - 5 = 0

Step-by-step explanation:

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Equation of line is y = mx +c

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Now m = \frac{y2 - y1}{x2 - x1}

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so, slop = \frac{6}{12}

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3 years ago
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Answer:

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Step-by-step explanation:

Step one:

Given data

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